Answer:
use symolab
Step-by-step explanation:
<1, 1, 1> × <1, 0, 1> = <1, 0, -1>
The cross product of the normals of the planes gives the direction vector of their line of intersection.
Answer:
10. y=2x+1 y = -1/2x +1
11. y=-1/3x +6 y = 3x -4
12. y=-5x-18 y=1/5x + 14/5
Step-by-step explanation:
To write the equation of a line we must have a slope and a point. To find the slope, we use the slope from the equations for parallel lines and modify it for perpendicular lines.
10. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope here is 2. The parallel slope is 2 and the perpendicular slope is the negative reciprocal or -1/2.
Parallel Perpendicular
(y-1)=2(x-0) (y-1)==-1/2(x-0)
y-1=2x y-1 = -1/2 x
y=2x+1 y = -1/2x +1
11. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope here is -1/3. The parallel slope is -1/3 and the perpendicular slope is the negative reciprocal or 3.
Parallel Perpendicular
(y-5)=-1/3(x-3) (y-5)=3(x-3)
y-5=-1/3x+1 y-5 = 3x - 9
y=-1/3x +6 y = 3x -4
12. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope here is -5. The parallel slope is -5 and the perpendicular slope is the negative reciprocal or 1/5.
Parallel Perpendicular
(y-2)=-5(x--4) (y-2)=1/5(x--4)
y-2=-5(x+4) y-2 = 1/5(x +4)
y-2=-5x -20 y-2 = 1/5x +4/5
y=-5x-18 y=1/5x + 14/5
The simplified answer to that radical is attached
