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KengaRu [80]
3 years ago
14

Sandy works at a clothing store. She makes $9 per hour plus earns 10% commission on her sales. She worked 75 hours over the last

two weeks and had a total of $1,549 in sales before taxes.
Which of the following is closest to how much she will earn in hourly wages and commission for those two weeks?

A.$830
B.$222
C.$155
D.$675

i think its D.
Mathematics
1 answer:
sesenic [268]3 years ago
6 0
Hourly wages.

She worked for 75 hours and makes $9 per hour.

Multiply:

\sf9\times75=675

You are correct, $675 is our answer.
You might be interested in
Type the correct answer in the box. Use numerals instead of words.
stiks02 [169]

Answer:

78

Step-by-step explanation:

(-5)•(-5) + 3•21= 25+ 63= 78

7 0
3 years ago
Find the equation of the line passing through (-2,8) and (5,-3)
Advocard [28]

y = -2/3x + 5

this is the slope intercept. -2/3 is the slope and 5 is where it intercepts the y axis.

hope this helps

4 0
3 years ago
In a survey of employees at a fast food​ restaurant, it was determined that 15 cooked​ food, 12 washed​ dishes, 21 operated the
andre [41]

This question is incomplete

Complete Question

In a survey of employees at a fast food​ restaurant, it was determined that 15 cooked​ food, 12 washed​ dishes, 21 operated the cash​ register, 7 cooked food and washed​ dishes, 6 cooked food and operated the cash​ register, 6washed dishes and operated the cash​ register, 4 did all three​ jobs, and 7 did none of these jobs

(a) Only cooked food?

(b) Only operate the cash register?

Answer:

(a) Only cooked food?

6

(b) Only operate the cash register?

13

Step-by-step explanation:

From the above question, we have the following information:

15 cooked​ food

12 washed​ dishes

21 operated the cash​ register

7 cooked food and washed​ dishes

6 cooked food and operated the cash​ register

6washed dishes and operated the cash​ register

4 did all three​ jobs

7 did none of these jobs

(a) Only cooked food?

This would be calculated as

Number of people that cooked food + Number of people that did all three jobs - Number of people that cooked food and washed​ dishes - Number of people that cooked food and operated the cash​

= 15 + 4 - 7 - 6

= 19 - 13

= 6

Therefore ,only 6 people cooked food

(b) Only operate the cash register?

This would be calculated as

Number of people that operated cash register + Number of people that did all three jobs - Number of people that cooked food and operated the cash​ register - Number of people that washed dishes and operated the cash​ register

= 21 + 4 - 6 - 6

= 25 - 12

= 13

Therefore, only 13 people operated cash register.

7 0
3 years ago
A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec
Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (<em>n</em> ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18

The sample size is, <em>n</em> = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191

(a)

The null hypothesis is:

<em>H</em>₀: The usual load is 13 credits, i.e. <em>μ</em> = 13.

Assume that the significance level of the test is, <em>α</em> = 0.05.

Construct a (1 - <em>α</em>) % confidence interval for population mean to check the claim.

The (1 - <em>α</em>) % confidence interval for population mean is given by:

CI=\bar x\pm z_{\alpha/2}\times SE

For 5% level of significance the two tailed critical value of <em>z</em> is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct the 95% confidence interval as follows:

CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)

As the null value, <em>μ</em> = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0
3 years ago
Read 2 more answers
What is the square root of 1/25
wolverine [178]
First simplify the square root of 1/25

-√1/25

Rewrite using the quote by rule for radicals.

-√1/√25

Any root of 1 is 1

-1/√25

Simplify the denominator. (find the square root of 25)

-1/5

The result can be shown in both exact and decimal forms.
Exact form: -1/5
Decimal form: -0.2

6 0
3 years ago
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