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NemiM [27]
3 years ago
7

H(y)=9/5 • 2y at y=-2

Mathematics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

H( - 2) = - 7  \frac{1}{5}

Step-by-step explanation:

We want to evaluate the equation

H(y) =  \frac{9}{5}  \times 2y

at y=-2

We just have to substitute to obtain;

H( - 2) =  \frac{9}{5}  \times 2 \times  - 2

We now multiply to get:

H( - 2) =  \frac{9}{5}   \times  - 4

This is the same as:

H( - 2) =  \frac{9}{5}  \times \frac{ - 4}{1}

We multiply the numerators separately and denominators separately to get:

H( - 2) =  \frac{9 \times  - 4}{5 \times 1}

H( - 2) =  \frac{ - 36}{5}

This implies that

H( - 2) = - 7  \frac{1}{5}

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Answer:

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Step-by-step explanation:

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It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

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2 years ago
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Here is your new equation:

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To get your answer, you need to add 12 and 1. Add:

12+1 = 13

That means:

\bf f(3)=13

<em>If you have any questions, feel free to ask in the comments! :)</em>

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Step-by-step explanation:

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