Question

H(y)=9/5 • 2y at y=-2

Answer 1

Answer:

$H( - 2) = - 7 \frac{1}{5}$

Step-by-step explanation:

We want to evaluate the equation

$H(y) = \frac{9}{5} \times 2y$

at y=-2

We just have to substitute to obtain;

$H( - 2) = \frac{9}{5} \times 2 \times - 2$

We now multiply to get:

$H( - 2) = \frac{9}{5} \times - 4$

This is the same as:

$H( - 2) = \frac{9}{5} \times \frac{ - 4}{1}$

We multiply the numerators separately and denominators separately to get:

$H( - 2) = \frac{9 \times - 4}{5 \times 1}$

$H( - 2) = \frac{ - 36}{5}$

This implies that

$H( - 2) = - 7 \frac{1}{5}$