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NemiM [27]
3 years ago
7

H(y)=9/5 • 2y at y=-2

Mathematics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

H( - 2) = - 7  \frac{1}{5}

Step-by-step explanation:

We want to evaluate the equation

H(y) =  \frac{9}{5}  \times 2y

at y=-2

We just have to substitute to obtain;

H( - 2) =  \frac{9}{5}  \times 2 \times  - 2

We now multiply to get:

H( - 2) =  \frac{9}{5}   \times  - 4

This is the same as:

H( - 2) =  \frac{9}{5}  \times \frac{ - 4}{1}

We multiply the numerators separately and denominators separately to get:

H( - 2) =  \frac{9 \times  - 4}{5 \times 1}

H( - 2) =  \frac{ - 36}{5}

This implies that

H( - 2) = - 7  \frac{1}{5}

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