3 years ago

If 5x-7=13x+17, what is 6(x-4)?

Mathematics

1 answer:

Luba_88 [7]3 years ago

8 0

30 I believe, sorry if I am wrong, I am bad at math and history.

You might be interested in

Find the value of csc theta, I'd cos thetA =-1/4;180< theta<270

ss7ja [257]

Caca because I said so luv

3 0

3 years ago

Read 2 more answers

Factor x3y6 + 27z42. (xy3 + 3z39)(x2y9 – 3xy3z39 + 9z1,521) (xy3 + 3z39)(x2y6 – 3xy3z39 + 9z78) (x3y6 + 27z42)(x6y12 – 27x3y6z42

Licemer1 [7]

Answer:

$x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})$

Step-by-step explanation:

Given

$x^3y^6 + 27z^{42$

Required

Factor

Express both terms as a cube

$x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3$

Let

$a =(xy^2)$

$b = (3z^{14})$

So:

$x^3y^6 + 27z^{42} = a^3 + b^3$

Using sum of cubes:

$a^3 + b^3 = (a + b)(a^2 - ab + b^2)$

So:

$x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)$

Substitute in, values of a and b

$x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)$

$x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})$

5 0

3 years ago

Read 2 more answers

What is 2+2.8/2.45*5.654=

alekssr [168]

8.4617....

Hope this helped you :)

6 0

3 years ago

Read 2 more answers

Find the sum in its simplest form. 6/9 + 6/9 will give brainlist for best answer

sukhopar [10]

Answer:

→Step 1:

$\frac{6}{9} + \frac{6}{9}$

write the equation

→Step 2:

$\frac{6 + 6}{9}$

after taking LCM of 6/9 and 6/9 we get( 6+6)/9

→step 3:

$\frac{12}{9}$

after adding 6 and 6 we get 12

→Step 4:

$\frac{4}{3}$

after dividing numerator and denominator by 3 we get 4/3

→step5:

$1.334$

finally we get 1.334✓

hope it helped you:)

7 0

3 years ago

Read 2 more answers

Trigonometry help please

Taya2010 [7]

Answer:

a rectangular field.The length of rectangular field is three times the breadth of the field. If the area of the path is 500 m square ,then find the length and breadth

8 0

3 years ago