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LiRa [457]
3 years ago
11

If 5x-7=13x+17, what is 6(x-4)?

Mathematics
1 answer:
Luba_88 [7]3 years ago
8 0
30 I believe, sorry if I am wrong, I am bad at math and history.
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Licemer1 [7]

Answer:

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

Step-by-step explanation:

Given

x^3y^6 + 27z^{42

Required

Factor

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x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3

Let

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b = (3z^{14})

So:

x^3y^6 + 27z^{42} = a^3 + b^3

Using sum of cubes:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

So:

x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)

Substitute in, values of a and b

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

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Answer:

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→Step 4:

\frac{4}{3}

<em>after dividing numerator and denominator</em> by 3 we get 4/3

→step5:

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