Answer:
(5,-0.5)
Step-by-step explanation:
You need to take the avarage of each number. That will get you to the midpoint.
Answer:
give me specfic measurments and ill give you the anwser
Step-by-step explanation:
Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error:

For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.







With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Answer:
you mulitply 25 then divide it by 5 and add in the variable
Step-by-step explanation:
hope it helps