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LenKa [72]
4 years ago
13

The box plot suggests that Olga served fewer than what number of aces during about 75 % , percent of tennis matches?

Mathematics
2 answers:
lys-0071 [83]4 years ago
4 0

Answer:

10

Step-by-step explanation:

Khan Academy

anastassius [24]4 years ago
3 0

Answer:

10

Step-by-step explanation:

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What is the midpoint of the vertical line segment (5,4) and (5,-5)
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(5,-0.5)

Step-by-step explanation:

You need to take the avarage of each number. That will get you to the midpoint.

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What is the perimeter of the plot of the parking lot?​
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A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b
nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

p = 0.1

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}

0.04\sqrt{n} = 0.588

\sqrt{n} = \frac{0.588}{0.04}

\sqrt{n} = 14.7

(\sqrt{n})^{2} = (14.7)^{2}

n = 216

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0
4 years ago
Seven more than the quotient of a number b and 25 is greater than 5
grin007 [14]

Answer:

you mulitply 25 then divide it by 5 and add in the variable

Step-by-step explanation:

hope it helps

7 0
3 years ago
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