Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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Answer:
don't under stand your question please
P=3 and p=-1
First you subtract the number without a variable to the other side, so subtract one from seven, and subtract five from eight. After that just divide to make p by its self and you get the answer!!
Answer:
the required probability is 0.09
Option a) 0.09 is the correct Answer.
Step-by-step explanation:
Given that;
mean μ = 7
x = 4
the probability of exactly 4 bridge construction projects taking place at one time in this state = ?
Using the Poisson probability formula;
P( X=x ) = ( e^-μ × u^x) / x!
we substitute
P(X = 4) = (e⁻⁷ × 7⁴) / 4!
= 2.1894 / 24
= 0.0875 ≈ 0.09
Therefore the required probability is 0.09
Option a) 0.09 is the correct Answer.