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Tom [10]
3 years ago
13

9^6 = x^3 x9^3 solve for x

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0

Answer:

x = 9

Step-by-step explanation:

{9}^{6}  =  {x}^{3}  \times  {9}^{3}

{9}^{6}  = 729 {x}^{3}

{x}^{3}  =  \frac{ {9}^{6} }{ {9}^{3} }

{x}^{3}  =  {9}^{3}

{x}^{3}  = 729

\boxed{\green{x = 9}}

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I need help answering all of these
Mashcka [7]

Answer:

A)-7

B)2

C)-2

D)-4

Step-by-step explanation:

7 0
3 years ago
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Megan surveyed a random sample of 60 students at her school and found that 42 of them ride the bus to school each day. if there
Dmitry_Shevchenko [17]
42/60, x/320. 320/60=5.33333, 42*5.33333=224. So, about 224 students would ride the bus.
4 0
3 years ago
(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate
OverLord2011 [107]

Answer:

t=0      Sugar = 0 Kg

t=1min Sugar=0.27 Kg

Step-by-step explanation:

Data

Tank = 2640 L (pure water)

Sol=0.09kg Sugar per liter

Vin = Vout = 3L/min

Sugar in the beginning = ?

if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;

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7 0
3 years ago
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If K = {(x, y)|x - y = 5}, find the corresponding range of y for the domain {0, 2, 4}. {-5, -3, -1} {0, 2, 4} {5, 7, 9}
Aleks04 [339]

Answer:

The range = {-5 , -3 , -1} ⇒ first answer

Step-by-step explanation:

* In any equation the values of x are the domain of it and

 the values of y are the range of it

* So to find the range of any equation substitute the values

 of x (domain) in the equation to get the corresponding

  values of y (range)

* In the problem

∵ K = {(x , y): x - y = 5}

∵ The domain is {0 , 2 , 4}

* Lets find K(0) , K(2) , K(4)

∵ K(0) = (0) - y = 5

∴ -y = 5 ⇒ Multiply both sides by -1

∴ y = -5

∵ K(2) = (2) - y = 5

∴ 2 - y = 5 ⇒ subtract 2 from both sides

∴ -y = 3 ⇒ Multiply both sides by -1

∴ y = -3

∵ K(4) = (4) - y = 5

∴ 4 - y = 5 ⇒ subtract 4 from both sides

∴ -y = 1 ⇒ Multiply both sides by -1

∴ y = -1

* The range = {-5 , -3 , -1}

8 0
3 years ago
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Find the number of kilowatt-hours of energy used when a 110-watt light bulb burns for 215 hours.
fenix001 [56]
We determine the kilowatt-hour by multiplying the energy in kilowatt and the time in hours. We do as follows:

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kWh = 23.65 kWh

Hope this answers the question. Have a nice day.
5 0
3 years ago
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