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Tom [10]
3 years ago
13

9^6 = x^3 x9^3 solve for x

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0

Answer:

x = 9

Step-by-step explanation:

{9}^{6}  =  {x}^{3}  \times  {9}^{3}

{9}^{6}  = 729 {x}^{3}

{x}^{3}  =  \frac{ {9}^{6} }{ {9}^{3} }

{x}^{3}  =  {9}^{3}

{x}^{3}  = 729

\boxed{\green{x = 9}}

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If EH = 76, calculate DI.
Montano1993 [528]

Answer:

DI = 38

Step-by-step explanation:

Δ EHC and Δ DIC are similar and ratios of corresponding sides are equal, that is

\frac{DI}{EH} = \frac{DC}{EC} , substitute values

\frac{DI}{76} = \frac{1}{2}  ( cross- multiply )

2DI = 76 ( divide both sides by 2 )

DI = 38

4 0
3 years ago
Please show me step by step how to solve this problem 3(-8+4v)=8v ?
Nadusha1986 [10]
So we know that:
3(-8 + 4v) = 8v
To find v, first simplify the left hand side:
-24 + 12v = 8v
Then group the "v's" over to the right:
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Hope this helped
8 0
3 years ago
A coffee shop sells regular coffee in three sizes. The table shows the sizes of each regular coffee sold throughout the day. Wri
kenny6666 [7]

Answer:

c) bajo: $1.62; mediano: $1.80; grande: $2.03

Step-by-step explanation:

Insert numbers from the table into a linear equation (ignore time column) and use Cramer's Rule.

55x+53y+54z=299.12

17x+22y+25z=117.89

30x+23y+29z=148.97

x, bajo = 1.62

y, mediano = 1.8

z, grande = 2.03

4 0
3 years ago
Find an equation of the plane that passes through the point P0 = (6, 3, 2) and is parallel to the xy-plane. g
Nutka1998 [239]

The <em>xy</em>-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.

Then the equation of the plane through (6, 3, 2) that is parallel to the <em>xy</em>-plane has equation

〈<em>x</em> - 6, <em>y</em> - 3, <em>z</em> - 2〉 • 〈0, 0, 1〉 = 0

==>   <em>z</em> - 2 = 0

==>   <em>z</em> = 2

3 0
3 years ago
What can 4/6 be simplified into
Charra [1.4K]
Since both 4 and 6 are divisible by 2, it becomes 2/3<span />
6 0
3 years ago
Read 2 more answers
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