The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
A. 112 m^2
Step-by-step explanation:
If the scale factor is 4, the area of the larger figure is 4^2 times that of the smaller one.
... (7 m^2)·4^2 = 112 m^2
_____
The scale factor for area is the square of the scale factor for linear dimensions. When we talk about a scale factor without qualification, we mean the scale factor for linear dimensions.
Marco does 70 extra math problems each week. 14(5)=70
The graph crosses the x axis 3 times so there are 3 roots.
B
Answer: The entire trip is 62.5 miles
Step-by-step explanation:
25 miles = 0.4x
Divide both sides by 0.4
25/0.4 = 62.5 miles