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3 years ago

In △ABC , AC=12 in. , BC=1.5 in. , and m∠C=63° .

1 answer:

0 0

Using the Side Angle Side Formula
Area = ½ • side 1 • sine (A) • side 2
Area = ½ • 12 * sine (63°) * 1.5
Area = ½ • 12 * 0.89101 * 1.5
Area = 8.01909 
Area = 8.02 rounded

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Minneapolis, Minnesota and Portland, Oregon have very similar latitudes. (Latitude measures how far north or south a place is, w

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3 years ago

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How do i find the vertical asymptote?

levacccp [35]

Answer:

find the value of x that makes the denominator zero: x = 7

Step-by-step explanation:

A vertical asymptote shows up where the denominator is zero. As the denominator gets closer to zero, the function value gets larger without bound (unless there is a numerator factor that cancels the one in the denominator).

To find the value of x at the vertical asymptote, solve the equation ...

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3 years ago

Given: f(x) = 3x-7, g(x)=2x2 -3x+1, h(x)=4x+1, k(x) =-x2+3 Find: k(x) +g(x)

Afina-wow [57]

Answer:

k(x) + g(x) = x² - 3x + 4

General Formulas and Concepts:

Alg I

Combining like terms

Step-by-step explanation:

Step 1: Define

f(x) = 3x - 7

g(x) = 2x² - 3x + 1

h(x) = 4x + 1

k(x) = -x² + 3

Step 2: Find k(x) + g(x)

Substitute: k(x) + g(x) = -x² + 3 + 2x² - 3x + 1
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2 years ago

Cos(-170°) = _____ -cos10° cos10° cos(-10°)

ikadub [295]

The right answer for:

cos(-170°) = _____

is:

-cos10°

<h2>Explanation:</h2>

The cosine function is an even function, which means that for every point $(x,y)$ on the graph of $y=cos(x)$ then the point $(-x,y)$ also lies on the graph of the function. In other words, we can write:

$cos(-170^{\circ})=cos(170^{\circ})$

But:

$170^{\circ}=180^{\circ}-10^{\circ}$

So:

$cos(170^{\circ})=cos(180^{\circ}-10^{\circ})$

By property:

$cos(a-b)=cosacosb+sinasinb \\ \\ a=180^{\circ} \\ \\ b=10^{\circ} \\ \\ cos(170^{\circ} )=cos(180^{\circ} -10^{\circ})=cos180^{\circ} cos10^{\circ} +sin180^{\circ} sin10^{\circ} \\ \\ cos(170^{\circ})=-cos(10^{\circ})+0 \\ \\ \boxed{cos(170^{\circ})=-cos(10^{\circ})}$