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netineya [11]
4 years ago
11

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

Mathematics
1 answer:
seraphim [82]4 years ago
3 0

21.6 units

Calculate the length of the 2 inclined sides using the distance formula

d = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 3, 3 ) and (x₂, y₂ ) = (3, 4 )

d = √(3 + 3 )² + (4 - 3)² = √(36 + 1 ) = √37

repeat for (x₁, y₁ ) = (- 3, 3 ) and (x₂, y₂ ) = (3, - 3 )

d = √(3 + 3 )² + (- 3 - 3 )² = √(36 + 36 ) = √72

the vertical side has a length of 7 units

perimeter = √37 + √72 + 7 = 21.6 ( nearest tenth of a unit )



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Answer:

7) 4 \ log_3(x) - 4 \ log_3(y)

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Step-by-step explanation:

log_3 (\frac{x}{y})^{4}

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Use Logarithm of a Quotient which states

log_b \frac{M}{N}  = log_b M-log_bN

And also use Logarithm of a Power which states

log_b\ M^{n} = n\log_bM

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So using these two properties,

7. 4 \ log_3(x) - 4 \ log_3(y)

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For #9, use the same logarithm propertied

log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)

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#11 is also the same concept

log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)

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Hope this is what you were looking for and helps you! Have a nice day/night :)

4 0
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