Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
b² = 225
b = 15
Answer: the length of the common external tangent is 15.
Answer:
Q(2, 6 )
Step-by-step explanation:
Using the midpoint formula
let the coordinates of Q = (x, y ), then
0.5(x + 10) = 6 ( multiply both sides by 2 )
x + 10 = 12 ( subtract 10 from both sides )
x = 2
and
0.5(y + 6) = 6 ( multiply both sides by 2 )
y + 6 = 12 ( subtract 6 from both sides )
y = 6
Coordinates of Q = (2, 6 )
7 x 1 = 7
7 x 2 = 14
7 x 3 = 21
7 x 4 = 28
7 x 5 = 35
