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Sonbull [250]
1 year ago
13

HELP MEEEEEEEEE PLEASEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Nadya [2.5K]1 year ago
4 0

Answer: 58, 122

Step-by-step explanation:

x+2x+6=180\\\\3x+6=180\\\\x+2=60\\\\x=58\\\\\therefore 180-x=122

liraira [26]1 year ago
4 0

Answer:

smaller angle=58°

larger angle=122°

Step-by-step explanation:

let larger number=y

y=2x+6

also x+y=180

x+2x+6=180

3x=180-6

3x=174

x=174/3=58

y=180-58=122

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For every pound a company spends on advertising, it spends £0.43 on its website. Express the amount spent on advertising to its
Wittaler [7]

Answer:

£1 : £0.43

Step-by-step explanation:

So to make the ratio, you need the amount of money spent on advertising and the money spent on its website

Website money = £0.43

Advertising money = £1

£1 : £0.43

6 0
3 years ago
Hi guys! could you please help me out with this real quick? Thanks y'all!<br><br> -Grace :))
Alla [95]

Answer:

B

Step-by-step explanation:

is the only one with a constant rate of change which would be -2

8 0
3 years ago
1. The probability of telesales representative making a sale on a customer call is 0.15.
Mumz [18]

Answer:

1c

 n = 33

1d

 n = 19

Step-by-step explanation:

From the question we are told that

   The  probability of telesales representative making a sale on a customer call is  p = 0.15

     The mean is  \mu  =  5

Generally the distribution of sales call  made by a  telesales representative follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators  

Generally the mean is mathematically represented as

     \mu =  n*  p

=>  5= n *  0.15

=>  n = 33

Generally the least number of calls that need to be made by a representative for the  probability of at least 1 sale to exceed 0.95 is mathematically represented as

      P( X \ge 1) = 1 - P( X < 1 ) > 0.95

=>    P( X \ge 1) = 1 - P( X =0 ) > 0.95

=>    P( X \ge 1) = 1 - [ ^{n}C_0 *  (0.15 )^0 *  (1- 0.15)^{n-0}] > 0.95

=>    1 - [1  *  1*  (0.85)^{n}] > 0.95

=>    [(0.85)^{n}] > 0.05

taking natural  log of both sides

n = \frac{ln(0.05)}{ln(0.85)}

=>  n = 19

3 0
3 years ago
Which of the following statements is needed in order to prove these triangles are congruent by AAS?
creativ13 [48]

Answer:

RQ\cong UT

Step-by-step explanation:

Two triangles are congruent by AAS postulate if two adjacent corresponding angles are congruent and the next adjacent sides to any of the angles is are also congruent. The adjacent sides should not be in between the two congruent angles.

From the triangles RQS and UTV

\angle R\cong \angle U\\\angle S\cong \angle V

The adjacent side to \angle R is RQ and for \angle U is UT.

Similarly, the adjacent side to \angle S is QS and for \angle V is TV.

So, the possible sides that could be congruent by AAS postulate are:

RQ\cong UT or QS\cong TV

So, the correct option is RQ\cong UT

5 0
3 years ago
The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p). If the volume of a gas i
andre [41]
The answer is 12.8 cm³

<span>The volume ( v) of a gas in a container at a constant temperature varies inversely as the pressure (p):
v = k/p
p * v = k  (k - constant)

p1v1 = k
p2v2 = k
So, p1v1 = p2v2

v1 = 24 cm</span>³
p1 = 16 lb
v2 = ?
p2 = 30 lb

24 * 16 = x * 30
384 = x * 30
x = 384 / 30
x = 12.8 cm³
3 0
3 years ago
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