Possible dimension of a box with a volume of 100 cubic cm
10 x 10 x 1 = 100
10 x 5 x 2 = 100
5 x 5 x 4 = 100
Surface area:
10 x 10 x 1 dimensions:
10 x 10 = 100 x 2 = 200 sq.cm
10 x 1 = 10 x 4 = 40 sq. cm
240 sq. cm * $0.05 / 100 sq.cm = $0.12 per box
0.12 per box * 100 boxes = $12
10 x 5 x 2 dimension
10 x 5 = 50 x 2 = 100 sq. cm
10 x 2 = 20 x 2 = 40 sq. cm
5 x 2 = 10 x 2 = 20 sq. cm
160 sq. cm * $0.05/100 sq. cm = $0. 08 per box
0.08 per box * 100 boxes = $8
5 x 5 x 4 dimension
5 x 5 = 25 x 2 = 50 sq. cm
5 x 4 = 20 x 4 = 80 sq. cm
130 sq. cm * $0.05/100 sq. cm = $0.065 per box
0.065 per box * 100 boxes = $6.50
The best dimension to use to have the least cost to make 100 boxes is 5 x 5 x 4. It only costs $6.50 to make 100 boxes.
Answer:

Step-by-step explanation:
The radius r can be found from the relationship

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

See the attached image.
The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt

m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t

That is the expression for V at time t. I hope I was able to help. Have a good day.
She could switch them around by grouping them into groups of 4s, 3s, 2s, or 5s.