6-4x=-2
-6. -6
-4x=-8
/-4. /-4
X=2
The answer to a "sum and difference" problem is that the larger number is the average of those given: (43 +15)/2 = 29.
The smaller number can be computed any of several ways, but subtracting the difference works: 29 -15 = 14
The larger number is 29.
The smaller number is 14.
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You can let the numbers be a and b, and let the sum and difference be s and d. Then you have
.. a + b = s
.. a - b = d
Add these two equations, and you find "b" is eliminated:
.. 2a = s + d
.. a = (s + d)/2 . . . . . . the average of the sum and difference
.. b = a - d . . . . . . . . . from the second equation
This solution is generic. Even if you have to "show work" on such a problem, you can use this known result to check your work.
L=s+4 bc lisa is 4 and we don't know who old is Sammy..
Wow ! Now THERE's an incentive ! I'm just glad I got in
early enough so that there's an answer block left open.
If you should happen to glance at these three problems,
you'll notice that they're all the same problem, just with
different numbers. So if somebody showed you how to do
ONE of them, you'd know how to do ALL of them.
1). Markup = 10% of $50 = 0.1 x $50 = $5
Selling price = ($50 + $5) = $55 .
2). Markup = 60% of $80 = 0.6 x $80 = $48
Selling price = ($80 + $48) = $128 .
3). Markup = 25% of $140 = 0.25 x $140 = $35
Selling price = ($140 + $35) = $175 .
Answer:
$5,674.30
Step-by-step explanation:
Use the Compound Amount formula:
A = P(1 + r/n)^(n*t), where r = APR as a decimal fraction = 0.1499
and n = 12 (compounded monthly).
Then A = $2,000(1 + 0.1499/12) )^(7*12)
= $2,000(1 + 0.0125)^84
= $2,000(1.0125)^84 = $2,000(2.837) = $5,674.30
