Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense
Eight hundred ninety four thousand, two hundred and seventeen. I hope this helps.
Given two functions, we can combine them in such a way so that the outputs of one function become the inputs of the other. ... 3, right parenthesis first and then substitute that result into f f ff to find our answer. ..... Problem 1 ..... end{aligned} (h∘g)(x)=h(g(x))=(g(x))2−2(g(x))=(x+4)2−2(x+4)=x2+8x+16−2x−8=x2+6x+8Define.
Exact form: x= NEGATIVE 6/7
The answer would be 40
-4(-2) = 8
8(5) = 40
