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love history [14]

3 years ago

7

Is color preference is a good predictor of condiment preference, and then describe whether condiment preference is a good predic

tor of color preference.

1 answer:

yawa3891 [41]3 years ago

8 0

Answer:

no it is not a color prefernce

Step-by-step explanation:

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Help plz? i don’t understand the example

nataly862011 [7]

Answer:

The example is telling you to first add up each number then divide by the amount of numbers that are present in the set. There are four in this example.

Secondly the difference between each data point will differ from each number. Basically subtract the sum from each number. Which is 5 in this case. But if its negative flip it to a positive.

Then add up each absolute value and divide by 4 twice.

7 0

3 years ago

Lunch costs $6.90. How much change will<br> Hector get from $20.00?

balandron [24]

Answer: 22

Step-by-step explanation:

5 0

2 years ago

Find t(2.5) if t (x)/\2 +2x

Semmy [17]

T(2.5) If t(x)= x^2 + 2x

where z = 2.5

t(x) = (2.5)^2 + 2(2.5)

6.25 + 5 =

11.25 = Ans

4 0

4 years ago

(-7x^2+3) + (4x^2+2x-1);<br> Find the sum or difference.

ivann1987 [24]

(-7x² + 3) + (4x² + 2x - 1)

-7x² + 3 + 4x² + 2x - 1

(-7x² + 4x²) + (3 - 1) + 2x collect like terms

-3x² + 2x + 2

hope this helps, God bless!

4 0

4 years ago

48% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually

oksian1 [2.3K]

Answer:

There is no sufficient evidence to support the executive claim

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.48$

The sample proportion is $\r p = 0.45$

The sample size is $n = 300$

The level of significance is $\alpha = 0.02$

The null hypothesis is $H_o : p= 0.48$

The alternative hypothesis is $H_a : p \ne 0.48$

Generally the test statistics is mathematically evaluated as

$t = \frac{\r p - p }{ \sqrt{ \frac{p(1 - p )}{n} } }$

=> $t = \frac{0.45 - 0.48 }{ \sqrt{ \frac{0.48 (1 - 0.48 )}{300} } }$

=> $t = -1.04$

The p-value is mathematically represented as

$p-value = 2P(z > |-1.04|)$

Form the z-table

$P(z > |-1.04|) = 0.15$

=> $p-value = 2 * 0.15$

=> $p-value = 0.3$

Given that $p-value > \alpha$ we fail to reject the null hypothesis

Hence we can conclude that there is no sufficient evidence to support the executive claim

5 0

3 years ago