Answer:
(-3, 5) radius- r= 5
Step-by-step explanation:
x^2+6x+y^2-10y=-9
Rewrite ^2+6x+y^2-10y=-9 in the form of the standard circle equation
(x-(-3))^2+(y-5)^2= 5^2
Therefore the circle properties are:
(a, b)=(-3, 5), r= 5
A is the answer. I hope that helps
13x - y = 3 .....(1)
x - 6y = -33 ......(2)
eqn (2) × 13
13x - 78y = -429 .....(3)
(3) - (1)
13x - 78y = -429
13x - y = 3
(-). (+). (-)
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- 77y = 431
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-77y = 431
y = 431 ÷ -77
y = -5.5
You'll get two X values because there is a modulus.
