Answer:
9 sqrt(2) /2 = PQ
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp/ hypotenuse
sin 45 = PQ = 9
9 sin 45 = PQ
9 sqrt(2) /2 = PQ
Answer:
x + 5 = 5×
7x - 5 = 2x
5x + 2x + x = 180
<u>8</u><u>×</u><u> </u> = 180
8 8
x = 22.5
The pattern is:
( a - b )² = a² - 2 a b + b² ( square of last term of binomial - the missing term)
x² - 2 · 8 · x + 8² = x² - 16 x + 64 = ( x - 8 )²
The missing term is: 64
Using slope-intercept form, y = mx + b where m = slope and b = y-intercept:
We know our slope is -6. This can be interpreted as -6/1, which rise-over-run-wise, means that when y changes by 6, x changes inversely by 1.
To find that y-intercept, though, we need to find the value of y when x = 0.
Use our point (-9, -3) to find this...
We want to add 9 to x so that it becomes 0.
According to our slope, this means subtracting 54 from y.
Our y-intercept is at (0, -57), with -57 being the value of b we put in our equation.

You could also just use point-slope form:
y - y¹ = m(x - x¹)
y - (-3) = -6(x - (-9))
y + 3 = -6(x + 9)
And convert to slope-intercept if you want:
y + 3 = -6x - 54
y = -6x - 57
Answer:
b option im not sure but
Step-by-step explanation: