The digit in the ten thousands place is ten times the digits in the thousands place. if that's helps
Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer:
N = -3.36
Step-by-step explanation:
5.6 x N= 2.24
-5.6 -5.6
N= -3.36
= 3 × 10-11
(scientific notation)
= 3e-11
(scientific e notation)
= 30 × 10-^12
(engineering notation)
(trillionth; prefix pico- (p))
= 0.0000000000
<span>(real number)</span>