29-11=18
18²+18²=p²
324+324=p²
p²=648
p=18√2
That's your answer.
Answer:
help me plzz
Step-by-step explanation:
The velocity of a particle moving along the x-axis is v(t) = cos(2t), with t measured in minutes and v(t) measured in feet per minute. To the nearest foot find the total distance travelled by the particle from t = 0 to t = π minutes
Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
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1. You have that:
- The trapezoids are similar.
- The larger base of the smaller trapezoid is 18 m and its area is 310 m².
- The larger base of the larger trapezoid is 32 m.
2. Then:
Sides=18/32
Sides=9/16
Area=(9/16)²
Area=81/256
3. Now, you can find the area of the larger trapezoid, as below:
81/256=310/x
81x=(310)(256)
x=79360/81
x=980 m²
Therefore, the answer is: The area of the larger trapezoid is 980 m².
<em>9/20+5/12=14/32/2 equals a over all 7/16</em>
