Step-by-step explanation:
(1, -3). (3, 0)
(0 + 3)/(3 - 1) = 3/2 is the slope
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
25$
Step-by-step explanation:
5=2
10=4
15=6
20=8
25=10
Answer:
<em>y = (-4/3)*x + 7</em>
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Step-by-step explanation:
The point-slope form of the equation of a line is: <em>y = a*x + b </em>
In the above equation, <em>a </em>is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]
The given line has a slope of -4/3, so that <em>a = -4/3 </em>
=> The equation of this line has a form as following: <em>y = (-4/3)*x + b (1)</em>
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As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:
<em>y = (-4/3)*x + b</em>
<em>=> -5 = (-4/3)*9 + b </em>
<em>=> -5 = -12 + b </em>
<em>=> b = 7</em>
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So that the equation in point-slope form of the given line is:
<em>y = (-4/3)*x + 7</em>
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