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ankoles [38]
1 year ago
6

in wereda election where four candidates appeared for election, the winning candidate received 36,000 votes which represented 45

% of the electorate. The other three candidates received 25%, 20% and 6% of votes each. How many of the electrorate voted?​
Mathematics
2 answers:
Bess [88]1 year ago
8 0

Answer:

73649 of 80000 (or 91.8%)

Step-by-step explanation:

<u>Note</u>:  An <u>electorate</u> is a person who is <u>entitled to vote</u> in an election - it does not necessarily mean they <u>have</u> voted in the election.

If 36000 votes represents 45% of the <em>electorate </em>(note: it does not say this figure represents 45% of the <em>votes</em>), then the total number of electorates is:

\implies \sf \dfrac{36000}{45}\times 100=80000

If three candidates received 25%, 20% and 6% <u>of the votes</u>, then the winning candidate received:

⇒ 100% - 25% - 20% - 6% = 49% of the votes

If the winning candidate received 36,000 votes, then:

⇒ 49% of the votes = 36,000 votes

Therefore, the total number of votes is:

\implies \sf \dfrac{36000}{49}{ \times 100=73469

To find the percentage of electorates that voted:

\implies \sf \dfrac{73469}{80000} \times 100=91.8\% \:\: (1\:d.p.)

Dmitry [639]1 year ago
7 0

Let's see

Total votes be x

  • 45% of x=3600
  • 0.45x=3600
  • x=3600/0.45
  • x=8000

Now total percentage of vote

  • 45+20+25+6=96%

Not voted=4%

Find not voted

  • 0.04(8000)
  • 320

Total voted

  • 8000-320
  • 7680
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99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

<h3>What is the margin of error in statistics?</h3>

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

The interval will be calculated as below:-

Confidence interval = mean +/- margin of error (E)

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sd = sqrt(variance) = sqrt(144) = 12

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Degree of freedom (df) = n - 1 = 16- 1 = 15

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Significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

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The margin of error will be:-

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