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ankoles [38]
1 year ago
6

in wereda election where four candidates appeared for election, the winning candidate received 36,000 votes which represented 45

% of the electorate. The other three candidates received 25%, 20% and 6% of votes each. How many of the electrorate voted?​
Mathematics
2 answers:
Bess [88]1 year ago
8 0

Answer:

73649 of 80000 (or 91.8%)

Step-by-step explanation:

<u>Note</u>:  An <u>electorate</u> is a person who is <u>entitled to vote</u> in an election - it does not necessarily mean they <u>have</u> voted in the election.

If 36000 votes represents 45% of the <em>electorate </em>(note: it does not say this figure represents 45% of the <em>votes</em>), then the total number of electorates is:

\implies \sf \dfrac{36000}{45}\times 100=80000

If three candidates received 25%, 20% and 6% <u>of the votes</u>, then the winning candidate received:

⇒ 100% - 25% - 20% - 6% = 49% of the votes

If the winning candidate received 36,000 votes, then:

⇒ 49% of the votes = 36,000 votes

Therefore, the total number of votes is:

\implies \sf \dfrac{36000}{49}{ \times 100=73469

To find the percentage of electorates that voted:

\implies \sf \dfrac{73469}{80000} \times 100=91.8\% \:\: (1\:d.p.)

Dmitry [639]1 year ago
7 0

Let's see

Total votes be x

  • 45% of x=3600
  • 0.45x=3600
  • x=3600/0.45
  • x=8000

Now total percentage of vote

  • 45+20+25+6=96%

Not voted=4%

Find not voted

  • 0.04(8000)
  • 320

Total voted

  • 8000-320
  • 7680
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The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre
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Answer:

For 124 chirps per minute the temperature is 68 ºF.

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Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

f(x)=b+mx

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

  • At 104 chirps per minute, the temperature is 63 ºF.
  • At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and  y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

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Therefore, the linear function is

y=\frac{1}{4} \cdot x+37

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (124)+37=68

For 68 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (68)+37=54

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