What is the Least common denominator of 11/4 and 5/6
2 answers:
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Answer:
Step-by-step explanation:
The equation for a circle is , where
is the vertex of the circle and
is the radius. Immediately, since the center of the circle is given, we know what
and
are.
is 230 and
is 220.
The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the <u>distance formula</u>, which is really just the <u>Pythagorean Theorem</u> rearranged. The formula states that , where
is the change in the x-coordinates of the two points and
is the change in the y-coordinates of the two points. Plug-in
for 60 and
for 50 to get
. Solve for
, arriving at
. Therefore, the radius of the circle is
.
Finally, we have all of the components to create the equation of the circle. Plug-in 230 for , 220 for
, and
for
.
The equation of the circle will be .
Hope this helps :)
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
