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lukranit [14]
3 years ago
11

What is the Least common denominator of 11/4 and 5/6

Mathematics
2 answers:
Arlecino [84]3 years ago
5 0

Hi

H

Upggpugupgupgug0bjlblblibib,

Aleks04 [339]3 years ago
3 0

Answer:

12

Step-by-step explanation:

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D<br> الا<br> 3x+3<br> 4x+2<br> Determine the value of mZDCB.
Anvisha [2.4K]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given Angles (4x + 2) and (3x + 3) are forming linear pair, so

  • 4x + 2 + 3x + 3 = 180

  • 7x + 5 = 180

  • 7x = 180 - 5

  • 7x = 175

  • x =  \dfrac{175}{7}

  • x = 25

now, let's find Angle DCB :

  • 3x + 3

  • (3 \times 25) + 3

  • 75 + 3

  • 78 \degree
8 0
3 years ago
HELP ASAP PLEASE, tell me if the answers are correct and help me put them in human words not the first one though (WILL GIVE BRA
Artist 52 [7]
The volume of a cone is pi times the radius squared times the height divided by three.
The volume of a cylinder is pi times the radius squared times the height.
The volume of a sphere is 4 divided by 3 times pi times the radius cubed.
Does this help?
4 0
3 years ago
Read 2 more answers
10. Contacts. Assume that 30% of students at a university
jonny [76]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) A normal model with mean 0.3 and standard deviation of 0.0458 should be used.

b) There is a 0.2327 = 23.27% probability that more than one third of this sample wear contacts.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 30% of students at a university wear contact lenses, hence p = 0.3.
  • We randomly pick 100 students, hence n = 100.

Item a:

np = 100(0.3) = 30 \geq 10

n(1 - p) = 100(0.7) = 70 \geq 10

Hence a normal model is appropriated.

The mean and the standard deviation are given as follows:

\mu = p = 0.3

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.3(0.7)}{100}} = 0.0458

Item b:

The probability is <u>1 subtracted by the p-value of Z when X = 1/3 = 0.3333</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.3333 - 0.3}{0.0458}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

1 - 0.7673 = 0.2327.

0.2327 = 23.27% probability that more than one third of this sample wear contacts.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

5 0
3 years ago
Answer and show work.<br><br> 1.) 9 - t = 3 (t -5) <br><br> 2.) 5 (5y + 1) =10y - 25
AlladinOne [14]

Answer:

1. 6

2. 2

Step-by-step explanation:

1. 9-t=3(t-5)

9-t=3t-15

+t +t

9=4t-15

+15 +15

<u>24</u>=<u>4t</u>

4 4

6=t

2.5(5y+1)=10y-25

25y+5=10y-25

+25 +25

25y+30=10y

-25 -25

<u>30</u>=<u>-15y</u>

15 15

2=y

6 0
3 years ago
Which of the following are true?
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D : because this make so much since duh . && watch yuu get it right !
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3 years ago
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