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Ray Of Light [21]
3 years ago
9

The number of customers that visit a local small business is 51,200 and has been continuously declining at a rate of 3.8% each y

ear. What is the approximate number of
customers that visit the business in 14 years?
Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

Final amount of customers =30141.44

Step-by-step explanation:

Amount of customer remaining

A= p(1-r/n)^(nt)

P= initial amount of customers

R= rate but it's a negative rate

N= number of times

T= number of years

A= final amount of customers

A= p(1-r/n)^(nt)

A= 51200(1-0.038/14)^(14*14)

A= 51200(1-0.0027)^196

A= 51200(0.9973)^196

A= 51200(0.5887)

A= 30141.44

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Friday's meeting needs 12 more sandwiches than Tuesday which needs 6 fewer than Monday which needs 20 more than wednesday which
Alina [70]

He will need 315 sandwiches to make each day next week

Step-by-step explanation:

The given:

  • Friday's meeting needs 12 more sandwiches than Tuesday
  • Tuesday needs 6 fewer than Monday
  • Monday needs 20 more than Wednesday
  • Wednesday needs 5 fewer than Thursday
  • The number of sandwiches ordered for the meeting that calls for the fewest is 50

We need to find how many sandwiches he will need to make each day next week

Assume that Tuesday needs x sandwiches

∵ Friday's meeting needs 12 more sandwiches than Tuesday

∵ Tuesday needs x sandwiches

- Add x by 12 to find Friday's need

∴ Friday needs = x + 12

∵ Tuesday needs 6 fewer than Monday

- That means Monday needs 6 more than Tuesday, add 6 to x

   to find Monday needs

∴ Monday needs = x + 6

∵ Monday needs 20 more than Wednesday

- That means Wednesday needs 20 less than Monday, subtract

   20 from Monday needs to find Wednesday needs

∴ Wednesday needs = x + 6 - 20 = x - 14

∵ Wednesday needs 5 fewer than Thursday

- That means Thursday needs 5 more than Wednesday, add 5 to

    Wednesday needs to find Thursday needs

∴ Thursday needs = x - 14 + 5 = x - 9

∵ The number of sandwiches ordered for the meeting that calls

   for the fewest is 50

- From the days needs above the fewest one is Wednesday, then

   equate Wednesday needs by 50

∵ Wednesday needs is x - 14

∴ x - 14 = 50

- Add 14 to both sides

∴ x = 64

Substitute x in each day needs to find the number of sandwiches

∵ Tuesday needs is x

∴ Tuesday needs = 64

∵ Friday needs is x + 12

∴ Friday needs = 64 + 12 = 76

∵ Monday needs is x + 6

∴ Monday needs = 64 + 6 = 70

∵ Wednesday needs = 50

∵ Thursday needs is x - 9

∴ Thursday needs = 64 - 9 = 55

Add the numbers of sandwiches of all day to find the number of sandwiches he will need to make each day next week

∵ The number of sandwiches = 76 + 64 + 70 + 50 + 55

∴ The number of sandwiches = 315

He will need 315 sandwiches to make each day next week

Learn more:

You can learn more about the word problems in brainly.com/question/3950386

#LearnwithBrainly

4 0
3 years ago
432 divided by the different between 279 and 63
Debora [2.8K]
The difference (I'm assuming you meant difference) between 279 and 63 is
279 - 63 = 216
so divide 432 by 216
432 / 216 = 2
so the answer is 2
8 0
4 years ago
Combine the like terms to create an equivalent expression:<br> -4p+(-6p)
kupik [55]

Answer:

-10p

Step-by-step explanation:

-4 - 6 = -10

7 0
3 years ago
Read 2 more answers
How do you know if it is a adding or subtraction problem when you combine like terms?
Snowcat [4.5K]
You look at the sign behind the second term. Here are some examples...

2x + 8 - 4x 
You are going to subtract 2x - 4x because there is a negative sign behind the 4x.

8y + 1 + y
You are going to add 8y + y because there is a positive sign behind the y.

4 + 2x - 5 + 7x
You are going to subtract 4 - 5 because there is a negative sign behind the 5.
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4 0
3 years ago
Find the Quadratice function <img src="https://tex.z-dn.net/?f=y%3Da%28x-h%29x%5E%7B2%7D" id="TexFormula1" title="y=a(x-h)x^{2}"
Pani-rosa [81]

Given:

Consider the quadratic function is

y=a(x-h)^2+k

With given vertex (5,8) and given point (1,3).

To find:

The equation of quadratic function.

Solution:

The quadratic function is

y=a(x-h)^2+k               ...(i)

Where, (h,k) is the vertex and a is a constant.

Vertex is (5,8). So,

(5,8)=(h,k)

h=5,k=8

Putting h=5,k=8 in (i), we get

y=a(x-5)^2+8           ...(ii)

The given point is (1,3). Putting x=1 and y=3 in  (ii), we get

3=a(1-5)^2+8

3-8=a(-4)^2

-5=16a

-\dfrac{5}{16}=a

Putting a=-\dfrac{5}{16} in (ii), we get

y=-\dfrac{5}{16}(x-5)^2+8

Therefore, the required quadratic function is y=-\dfrac{5}{16}(x-5)^2+8.

4 0
3 years ago
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