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Law Incorporation [45]

3 years ago

12

Please help i’m confused

1 answer:

Pavel [41]3 years ago

6 0

Answer:

The answer is A. t = 0.4n

Step-by-step explanation:

<em>See how on the graph, when n is 2, t is around 1? We just plug in 2 into n into the equation, t=0.4n. 0.4 times 2 is 0.8, so t=0.8. 0.8 is around 1, so a is right.</em><em> </em>If we tried the same thing with one of the other choices, like B. t=2.5n, then plugging in 2 into n would give us 2 times 2.5, which is 5. 5 is nowhere around 1, making it wrong.

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Step-by-step explanation:

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8 0

3 years ago

Which of the following is equivalent to<br> 60 1/2

kotykmax [81]

Answer:

30 or 120 /4

Step-by-step explanation:

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3 0

2 years ago

Solve the equation <br> 4b + 22 = 5(b + 4) − 1

djverab [1.8K]

4b + 22 = 5 (b + 4) - 1 (remove the parantheses)

4b + 22 = 5b + 20 - 1 (calculate)

4b + 22 = 5b + 19 (move the terms)

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-b = -3 (change the signs)

<em>b = 3</em>

3 0

3 years ago

Read 2 more answers

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

<em>Find out the distance BC</em>

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

<em>Find out the distance AB</em>

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

<em>Find out the area</em>

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago