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3 years ago

Rewrite y=4-2x in slope-intercept form.

1 answer:

5 0

This is already in slope intercept from. because the slope is -2 and the y intercept is 4. so if you put it in stander form you would get y=-2x+4

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Subtract 6 from me. Then multiply by 2. If you subtract 40 and then divide by 4, you get 8. What number am I?

aliina [53]

Answer:

Step-by-step explanation:

Let the number be "x"

We translate the word equation to algebraic equation.

First,

subtract 6 from me, so we have:

x - 6

Now,

Multiply by 2, so we have:

2(x-6)

Now,

Subtract 40, then divide by 4:

$\frac{2(x-6)-40}{4}$

Now, you get "8", so equate this to 8, we get:

$\frac{2(x-6)-40}{4}=8$

We now solve using algebra:

$\frac{2(x-6)-40}{4}=8\\2(x-6)-40=4*8\\2(x-6)-40=32\\2x-12-40=32\\2x-52=32\\2x=32+52\\2x=84\\x=42$

The number is 42

7 0

3 years ago

The total cost to rent a row boat is $14 times the number of hours the boat is used. Write an equation to model this situation i

Scrat [10]

The total cost is c the you just multiply 14 by the number of hours so it would be C=$14h

6 0

3 years ago

Strontium-90 has a half-life of about 29 years. After 65 years, about how many grams of a 25-gram sample will remain?

konstantin123 [22]

Answer:

Ending Amount = Beginning Amount / 2 ^ n

where 'n' = number of half-lives n = 65 / 29 = 2.2413793103

Ending Amount = 25 g / 2^2.2413793103

Ending Amount = 25 / 4.7284892286

Ending Amount = 5.2871009727 g = 5.29 g (rounded)

Step-by-step explanation:

3 0

3 years ago

In the set of real numbers, the first number greater than -4 is -3. true or false?

aniked [119]

Answer:

........ true ...

obviously -3 is greater than -4

3 0

2 years ago

Read 2 more answers

Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

$3x^2+5x=-1$

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

$D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13$

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0

3 years ago