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frutty [35]
3 years ago
10

Choose the compound below that should have the highest melting point according to the ionic bonding model. A) AlN B) MgO C) NaF

D) CaS E) RbI
Chemistry
2 answers:
iren2701 [21]3 years ago
5 0

Answer:

The correct answer is C.

Explanation:

The compound with the highest melting point according to the ion bond model is the one with the greatest electronegativity difference, since the ion bond is stronger and therefore more difficult to break.

The electronegativity difference is calculated as the electronegativity difference of the atoms of the molecule.

AlN: Al (1,61) and N (3,04) so the difference gives 1,43.

MgO: Mg (1,31) and O (3,44) so the difference gives 2,13.

NaF: Na (0,93) and F (3,98) so the difference gives 3,05.

CaS: Ca (1) and S (2,58) so the difference is 1,58.

RbI: Rb (0.82) and I (2.66) so the difference is 1.84.

Analyzing the different cases, we can conclude that the molecule that presents the greatest difference in electronegativity is NaF, so it will have a higher boiling point due to the attraction force between its atoms.

Have a nice day!

Virty [35]3 years ago
4 0

Answer:

C

Explanation:

Strength of ionic bonds depends on the relative sizes of the ions, the smaller the ions, the more efficiently they arrange themselves in a neat crystal lattice. NaF is the strongest purely ionic crystal in the list. Remember that the question emphasised the ionic bonding model. Though AlN is composed of small ions, but the compound has a high degree of covalent character and cannot be considered based purely on an ionic model as spelt out in te question.

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If 20 grams of C is formed from the combination or reaction of A and B chemicals in 10 minutes, 40 grams of C is formed in 20 minutes because the time is doubled so the concentration of C chemical is also doubled. If the time  is increased further, more concentration of C chemical is produced until the amount of chemicals A and B are present. If we put an enzyme in the solution, the time of the reaction can be reduced.

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Consider the fermentation reaction of glucose: C6H12O6 → 2C2H5OH + 2CO2 A 1.00-mol sample of C6H12O6 was placed in a vat with 10
inessss [21]

Answer:

% yield = 73.48 %

Explanation:

The fermentation reaction is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂          

The percent yield of C₂H₅OH is given by:

\% yield = \frac{m_{E}}{m_{T}} * 100

<em>where m_{E}: is the obtained mass of C₂H₅OH = 67.7g and m_{T}: is the theoretical mass of C₂H₅OH.     </em>

The theoretical mass of C₂H₅OH is calculated knowing that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH:  

m_{T} = mol * M

<em>where M: is the molar mass of C₂H₅OH =  46.068 g/mol</em>

m_{T} = 2 moles * 46.068 g/mol = 92.136 g                

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I hope it helps you!                  

3 0
3 years ago
A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr
umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0
4 years ago
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