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kondaur [170]
2 years ago
15

A small-sized woman has 6.4 x 10-3 moles of hemoglobin (molar mass of hemoglobin = 64, 456 g/mol) in her blood. Show your work

Chemistry
2 answers:
DaniilM [7]2 years ago
4 0

Answer:

Explanation:

Interesting question - especially if you are afflicted by something like Leukemia where it pays to know everything you can about Hemoglobin.

Molecules

1 mole of anything has 6.02 * 10^23 in this case molecules

6.4*10^-3 moles has x number of molecules

Set up the proportion

1/6.4*10^-3   =  6.02 * 10^23 molecule / x          Cross Multiply

x = 6.4*10^-3 * 6.02 * 10^23

x = 3.853*10^21 molecules

Mass Hemoglobin

1 mol of hemoglobin is 64456 grams

6.4*10^-3 moles = x grams                                  Cross multiply

x = 64456 * 6.4*10^-3

x = 412.5 grams of hemoglobin in this woman's body.

If you are American and think in pounds, then this is roughly a pound of hemoglobin.

Considering that you need hemoglobin to carry oxygen around to various organs, it is not an awful lot. That's the miracle of the human body.

nadezda [96]2 years ago
3 0

Answer: 412.52 g

Explanation:

64456 x 6.4 x 10^-3 = 412.5184

Tip: Look at the units and figure out the equation needed to find the answer

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A runner averages 8 minutes and 25 seconds per mile. What is her average velocity in miles per hour?
labwork [276]

8 minutes and 25 seconds is the same as 8.25 in decimal form.

Divide by 60 minutes.

60 / 8.25 = 7.27 miles per hour

Best of Luck!

6 0
3 years ago
What is the molecular formula of paradichlorobenzene that has a molar mass of 147.g/mol and an empirical formula of C3CIH2?
Gwar [14]

Answer:

the molecular formula of paradichlorobenzene is C6H4CL2

6 0
3 years ago
What health benefits can you get from consuming fiber? (select all that apply.)
mariarad [96]

Answer:

Above all are correct answer.

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6 0
2 years ago
A 55.0-kg skydiver free falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a ve
morpeh [17]
The kinetic energy of a moving object is calculated through the equation,
                                 KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity. Substituting the known values in the problem above,
                                KE = 0.5(55 kg)(16 m/s)²
                                KE = 7,040 J
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4 0
3 years ago
Read 2 more answers
Calculate the percent ionization of nitrous acid in a solution that is 0.230 M in nitrous acid. The acid dissociation constant o
djyliett [7]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.230M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.230-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .230 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.230-x ≈ 0.230

4.5x10^-4 = x^2/0.230

Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.01M/0.230M = .0434 or 

≈4.34% dissociation.
8 0
3 years ago
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