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Naily [24]
3 years ago
9

A student collected the data shown in the table below during an experiment.

Chemistry
1 answer:
pentagon [3]3 years ago
3 0

Answer: The answer is C.  A mercury thermometer is better to measure very small changes in temperature.

Explanation:

i took this quiz and this is the answer .

A) A mercury thermometer can measure the freezing point of a liquid that freezes at −80 °C.

B) An alcohol thermometer can measure the boiling point of a liquid that boils at 80 °C.

C) A mercury thermometer is better to measure very small changes in temperature.

D) An alcohol thermometer is better to measure the boiling points of colorless liquids.

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A weather balloon is filled with helium that occupies a volume of 5.57 104 L at 0.995 atm and 32.0°C. After it is released, it r
Alchen [17]

6.52 × 10⁴ L. (3 sig. fig.)

<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

P\cdot V = n\cdot R\cdot T,

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of gas particles in the gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume V of the gas. Rearrange the ideal gas equation for volume:

V = \dfrac{n \cdot R \cdot T}{P}.

Both the temperature of the gas, T, and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

  • T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K},
  • T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}.

The volume of the gas is proportional to its temperature if both n and P stay constant.

  • n won't change unless the balloon leaks, and
  • consider P to be constant, for calculations that include T.

V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}.

Now, keep the temperature at T_1 =258.65\;\text{K} and change the pressure on the gas:

  • P_1 = 0.995\;\text{atm},
  • P_2 = 0.720\;\text{atm}.

The volume of the gas is proportional to the reciprocal of its absolute temperature \dfrac{1}{T} if both n and T stays constant. In other words,

V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}

(3 sig. fig. as in the question.).

See if you get the same result if you hold T constant, change P, and then move on to change T.

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When 1 mole of bacl2 is dissolved in water it releases-8.67 kj/mil of energy. calculate h when 10.3 g of barium chloride is diss
dybincka [34]

An inorganic substance with the formula BaCl2 is barium chloride. It is one of the most popular barium salts that dissolve in water. Like the majority of other water-soluble barium salts, it is white, extremely hazardous, and gives flames a yellow-green tint.

When 1 mole of bacl2 is dissolved in water it releases-8.67 kj/mil of energy. calculate h when 10.3 g of barium chloride is dissolved to make a 1.00 l solution

In water, barium chloride is very soluble (as is the case with most ionic salts). In its dissolved condition, it is known to split into barium cations and chloride anions.

Let's first determine the total amount of CL- ions.

=> When HCl dissociates, one mol will produce H+ and one mol will produce CL-. Thus, . 2 moles yields. 2 mol CL-

=> One mole of Bacl2 will dissociate into one mole of Ba2+ and two moles of CL-. Therefore, 0.1 mol will result. two moles CL-

Hence, there are mols of CL- in total.

2+.2 = .4

=> Molarity:

Total moles of solute divided by liters of solution gives the molarity, M.

= .4/.5 = 0.8 M

As a result, 0.8 M is the molarity of CL- in solution.

To know more about Barium salts, click on the link below:

brainly.com/question/1300739

#SPJ4

8 0
1 year ago
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