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Snezhnost [94]
2 years ago
11

PLEASE HELP

Mathematics
2 answers:
vagabundo [1.1K]2 years ago
8 0

Answer:

C’(4, –2)

Step-by-step explanation:

In order to tranlate in the graph, you just have to add the translation to the point in the graph.

The point C is located in the graph in the coordenates (-2,-3).

Remember that the X axis is the horizontal and the Y axis is the vertical.

Now the triangle will be translated 6 units to the right, this is horizontal, meaning in the X axis, and as it is to the right, the number will be positive.

Point c=(-2,-3)\\x1=-2\\ translation=+6\\x2=x1+ translation\\x2=-2+6\\x2=4

Now to find the Y we know that the triangle will be translated 1 unit up, since it is up in the vertical axis that means that that unit will be positive.

Point c=(-2,-3)\\y1=-3 \\translation=+1\\y2=y1+ translation\\y2=-3+1\\x2=-2

And with that we have the new coordinates of C:

(4,-2)

rusak2 [61]2 years ago
7 0
C' ( 4, -2 )

this is the explanation sort of

c ( -2, -3 ), since it is translated six units to the right, add 6 to the x-coordinate and since it is translated one unit up, add 1 to the y-coordinate
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b) 1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

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And using the lower limit we got:

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And with the upper limit we got:

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So then the value of k =4 and the percentage is given by:

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Step-by-step explanation:

Previous concepts and Data given  

\mu =3.41 reprsent the population mean

\sigma=0.09 represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: 1-\frac{1}{k^2}

Part a

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

3 0
3 years ago
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