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3 years ago

I need help on this problem..please and thanks u

Mathematics

2 answers:

Triss [41]3 years ago

6 0

Answer:

Step-by-step explanation:

GarryVolchara [31]3 years ago

5 0

Answer:

A is on a line with the slope of 2/3

Step-by-step explanation:

the rule is that you do y2-y1 over x2-x1 which you do 4-2 over 8-5 and your final answer you would get 2/3.

hope this helped!

i am new here and my name is arrianna call me arri for short

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3 years ago

Given: angle Q is congruent to angle T and line QR is congruent to line TR

Ainat [17]

3. <u>Two angles and included side (ASA congruence theorem)</u>.

<u>Reason:</u> This is because, it is given that angle Q is congruent to angle T and line QR is congruent to line TR. Also, we proved in step 2 that $\angle PRQ\cong\angle SRT$ . Thus, we have two angles and the side included as congruent and thus, the two triangles are congruent.

4. <u>CSCT (Corresponding Sides of a Congruent Triangle)</u>

<u>Reason:</u> PR and SR are the corresponding sides of the congruent triangles $\Delta PRQ$ and $\Delta SRT$ , therefore, by the CSCT these corresponding sides have to be congruent.

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4 years ago

The length of a rectangle is 3 feet more than 5 times its width. The perimeter of the rectangle is 42 feet.

poizon [28]

42 = 2(W+L)

21= (W+L)

L= 3+5W)

21= W +(3+5W)

21= 3+6W

21-3=6W

18=6W

W=18/6

Answer:

w = PERIMETER/2 - LENGTH

<u>w = 42/2 - (3+5w)</u>

PS. I THINK THIS IS RIGHT. NOT TOO SURE, BUT MOST LIKELY.

6 0

3 years ago

Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.

miskamm [114]

[w + (h/tan θ)] × h

<h3>Further explanation</h3>

We aim is to find the area of the trapezoidal cross-section of the irrigation canal.

The formula for the area of the trapezoid is $\boxed{\boxed{ \ Area = \frac{1}{2} \times (a + b) \times h \ }}$

a & b = parallel sides
h = height

We assume the lower side is $\boxed{ \ a = w \ }$ and the upper side is b = x + w + x or $\boxed{ \ b = w + 2x \ }$ . See the attached picture.

In the right triangles located on the left and right of the trapezoid, we calculate the value of x based on trigonometric ratios namely tan of theta.

$\boxed{ \ tan \ \theta = \frac{opposite}{adjacent} \ }$

$\boxed{ \ tan \ \theta = \frac{h}{x} \ }$

$\boxed{ \ x = \frac{h}{tan \ \theta} \ }$

Substitute the equation of x to $\boxed{ \ b = w + 2x \ }.$

We get $\boxed{ \ b = w + \frac{2h}{tan \ \theta} \ }$

Finally all components are complete and can be substituted into a formula to calculate the area of a trapezoid.

$\circ \ \boxed{a = w}\\ \circ \ \boxed{ \ b = w + \frac{2h}{tan \ \theta} \ }\\\circ \ and \ h$

$\boxed{ \ Area = \frac{1}{2} \times (w + w + \frac{2h}{tan \ \theta}) \times h \ }$

$\boxed{ \ Area = \frac{1}{2} \times (2w + \frac{2h}{tan \ \theta}) \times h \ }$

$\boxed{ \ Area = \frac{1}{2} \times 2(w + \frac{h}{tan \ \theta}) \times h \ }$

Hence, the area of the trapezoidal cross-section of the irrigation canal is $\boxed{\boxed{ \ Area = (w + \frac{h}{tan \ \theta}) \times h \ }}$

<h3>Learn more</h3>

Find out the area of parallelogram brainly.com/question/4459688
The order of rotational symmetry of rhombus brainly.com/question/4228574
Find out the coordinates of the image of a point after the triangle is rotated 270° about the origin brainly.com/question/7437053

Keywords: the trapezoidal, cross-section of the irrigation canal, the area, the answer will be in terms of h, w, and θ, trigonometric ratios, tan, opposite, adjacent, height, sides

3 0

4 years ago

Read 2 more answers