What is the value of f(5) in the function below? f(x)=1/4 x 2^x

What is the answer to this equation <img src="https://tex.z-dn.net/?f=10%5Csqrt%7Bx%7D%2020" id="TexFormula1" title="10\sqrt{x}

AveGali [126]

Factor the expression
Use the properties of radicals
Simplify the roots
Calculate
And your solution will be 20 overall 5
Message me if you want me to write it all down!

8 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

2 years ago

8 star fruit cost $16. How many star fruit can you buy for $8?

kompoz [17]

Answer:

4 star fruit.

Step-by-step explanation:

16/8 = 2

each star fruit is 2 dollars

so 8/2 = 4

you can buy 4 star fruit for 8 dollars.

5 0

2 years ago

Read 2 more answers

what is the length of the side of a right triangle that has a hypotenuse that is 15 mm and a side of 9 mm

ratelena [41]

C) 27 mm
Hope this helps

4 0

2 years ago

Suppose Martin is a very talented used-car salesman. Whenever Martin talks to a new customer, there is a 50% chance

Likurg_2 [28]

Answer:

50x20=N-2xy=z

Step-by-step explanation:

there is polominals substraction,addtion and

divided

sana po makatulong po sa inyo

8 0

2 years ago

Read 2 more answers