Answer:
40%
Step-by-step explanation:
To find the percentage in each game, you divide the number of successful shots by the number of total shots. For game 1, this looks like: 8/22 = 0.3636, or 36%.
For game 2, this give us 40%, and for game 3, 43%.
Not sure if the question is asking for a game-by-game answer or a grand total, so we'll do both. To find the total percentage over the course of the games, add all the successful shots (8 + 6 + 10 = 24) and all the attempted shots (22 + 15 + 23 = 60), and divide the same way (24 / 60 = 40%).
For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>
Answer:
The answer is (18,15)
Step-by-step explanation:
Sorry if you get this wrong tho :/
