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tankabanditka [31]
3 years ago
12

Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?

Mathematics
1 answer:
Tomtit [17]3 years ago
7 0
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)
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