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IrinaVladis [17]
3 years ago
12

Marcy is drawing a stop sign to scale using letters that are 5 centimeters tall. What should be the width of her drawing of the

stop sign?
Mathematics
1 answer:
OverLord2011 [107]3 years ago
3 0

Answer:

20 centimeters

Step-by-step explanation:

i.e 5 x the number of characters in the stop sign.

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What is the amplitude of sin ?
sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

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  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

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Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

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3 years ago
Need Help ASAP I’m having trouble
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Answer:

ok

Step-by-step explanation:

nerd nerd nerd nerd lolololollool

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Raise the fraction to the highest term 1/5 to 15ths is \frac{3}{15}

<em><u>Solution:</u></em>

Given that we have to raise the fraction to the highest term 1/5 to 15ths

To raise a fraction to higher term, first you divide the larger denominator by them smaller denominator

Then multiply both the numerator and denominator by the same number, as a result that will give a new denominator.

Let "x" be the numerator of new fraction

\frac{1}{5} = \frac{x}{15}

To make the denominator 5 to 15 we have to multiply both numerator and denominator by 3

\frac{1 \times 3}{5 \times 3} = \frac{3}{15}

3 0
3 years ago
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