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Lesechka [4]
4 years ago
10

What is the vertex for g(x)=(x-3)+22

Mathematics
1 answer:
OverLord2011 [107]4 years ago
5 0

Answer:

Step-by-step explanation:

I think you meant g(x) = (x - 3)^2 + 22.

Compare this to    y - k = m(x - h)^2 (vertex form of the equation of a parabola)

and notice that k = 22 and h = 3.  Therefore, the vertex is at (h, k), which here is (3, 22).

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1) DC and DG

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\frac{ {y}^{3} -  {y}^{2}   + y + 3}{y + 1} \\  = \frac{ {y}^{3} +  {y}^{2}  - 2 {y}^{2}  - 2y  + 3y + 3}{x + 1}  \\  =   \frac{{y}^{2} (y + 1) - 2y(y + 1) + 3(y + 1)}{(y + 1)}  \\  =  \frac{(y + 1)( {y}^{2} - 2y + 3) }{(y + 1)}  \\  =  {y}^{2}  - 2y + 3

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Write the complex equation 8 + 3i in trigonometric form
Oxana [17]

Answer:

z = 8.544[cos(20.6) + isin(20.6)}

Step-by-step explanation:

Given

8 + 3i

Required

Rewrite in trigonometric form.

The trigonometric form of a complex equation is

z = r[cosθ + isinθ]

Let a = 3 and b = 8

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r is calculated by

r² = b² + a²

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θ = arctan(a/b)

Substituting 3 for a and 8 for b

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θ = 20.556°

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