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3 years ago

In ΔKLM, the measure of ∠M=90°, LK = 89, ML = 80, and KM = 39. What ratio represents the tangent of ∠K?

Mathematics

1 answer:

myrzilka [38]3 years ago

6 0

I am just trying to get point not right answer 89 ml = 80 km = 39

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Step-by-step explanation:

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3 years ago

What's the mean of 33,33,8,12,3,34,10

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Answer:

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Find the slope of ther line that goes through the points (-9,-4) and (-3,-6)

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Answer:

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Step-by-step explanation:

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3 years ago

Fernanda and Jose were working on an assignment in their geometry class in which they were to write the equation of the graph be

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Answer:

yes they both are wrong

Step-by-step explanation:

Center of the Circle is (h,I) which is (4,-3)

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radius is 4 units (3+1)

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$(x - h) {}^{2} + (y - k) {}^{2} = r {}^{2}$

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2 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

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Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

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3 years ago