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enyata [817]
3 years ago
14

In ΔKLM, the measure of ∠M=90°, LK = 89, ML = 80, and KM = 39. What ratio represents the tangent of ∠K?

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0
I am just trying to get point not right answer 89 ml = 80 km = 39
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Solve the system of equations y = 6x -7 <br><br> y = 3x + 11
max2010maxim [7]
If they both are equal to y, they must be equal to each other therefore,
6x-7 = 3x+11
3x = 18
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7 0
2 years ago
What is -5x + 3y= 12 in slope intercept form?
babymother [125]

Answer:

y = (5/3)x + 4

Step-by-step explanation:

-5x + 3y = 12 (What you start with)

3y = 12 + 5x (Adding 5x to both sides)

y = (5/3)x + 4 (Dividing the equation by 3)

8 0
3 years ago
If ∆JKL ≅ ∆PQR, which one of these is not a pair of corresponding parts? ​∠J and ∠P​ and ​∠L and ∠R​ and
Mandarinka [93]
When trying to prove that two triangles are congruent there are three congruency rules SAS, ASA and SSS. From the looks of things though I would say it would be the third one because just from the way you named the triangles I could tell that the two angles could correspond.

8 0
3 years ago
Carlos earns $11 per hour at his job. Let x represent the number of hours he worked in May. Let y represent the number of hours
Firlakuza [10]

11x+11y

11(x+y)

Explanation

Step 1

Let

Carlos earns == 11 per hour

x represents the number of hours he worked in May

the,

the amount he earned in Mayis

11\cdot x=11x

y represent the number of hours he worked in June.

the amount he earned in June was

11\cdot y=11y

Step 2

the amount of money he earned is May and June is the sum of the values

\begin{gathered} \text{total}= \\ 11x+11y \\ \text{if we factorize 11} \\ 11(x+y) \end{gathered}

I hope this helps you

5 0
1 year ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

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\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

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\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
2 years ago
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