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VikaD [51]
3 years ago
14

On the trip home, the Boden brothers had a 25-meter swimming race at a pool. If Hasson and Michael each swam at a constant rate,

who had a head start, and how big was the head start? Hasson’s Swim A graph with points (6, 9.6), (8, 11.8), (10, 14), and (12, 16.2). Michael’s Swim A 2-column table with 4 rows. Column 1 is labeled Time (seconds) with entries 6, 8, 10, 12. Column 2 is labeled Distance (meters) with entries 8.4, 11.2, 14, 16.8. had a head start of meters.
Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

Hasson had a head start of 3 meters

Step-by-step explanation:

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Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

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(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

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(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

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(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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