2 years ago

If h(x) =5 for the function h(x) =2x+1 what is the value of x

Mathematics

2 answers:

jeka942 years ago

8 0

Answer:

h (x) = 5

h (x) = 2x + 1

h (x) = 2 x 2 + 1 = 5

x = 2

skad [1K]2 years ago

4 0

Answer:

x = 2

Step-by-step explanation:

Its given that h(x) = 2x + 1

But its also given that h(x) = 5

$=> h(x) = 2x + 1 = 5$

$=> 2x + 1 = 5$

Solve the equation.

Substract 1 from both the sides.

$=> 2x + 1 - 1 = 5 - 1$

$=> 2x = 4$

Divide both the sides by 2.

$=> \frac{2x}{2} = \frac{4}{2}$

$=> x = 2$

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10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

<span>Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .</span>

7 0

2 years ago

Simplify the expression <br><br> 2(5x-1)

MrRissso [65]

The answer is 8x I believe

4 0

3 years ago

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