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3 years ago

Solve x2 – 2x = 15 by applying the quadratic formula.

Mathematics

1 answer:

julia-pushkina [17]3 years ago

5 0

Answer:

x = -60 and 20300

Step-by-step explanation:

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40% of the students passed both exams. 80% of the students passed the second exam. how many students (in percent) who passed the

navik [9.2K]

50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:

40/80 = 1/2 = 50%.

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7 0

1 year ago

A solution to a system of equations is at the point of intersection.

solniwko [45]

Answer:

true

Step-by-step explanation:

i dont have an explanation its just true

7 0

3 years ago

Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12

irina [24]

Answer:

Part 1) The perimeter is $P=6\sqrt{6}\ cm$

Part 2) The diagonal is $d=\sqrt{30}\ cm$

Step-by-step explanation:

The question in English is

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

$A=bh$

$A=12\ cm^2$

$bh=12$ ----> equation A

The base is twice the height

$b=2h$ ----> equation B

substitute equation B in equation A

$(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm$

Find the value of b

$b=2\sqrt{6}\ cm$

step 2

Find the perimeter of rectangle

The perimeter is given by

$P=2(b+h)$

substitute

$P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm$

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

$d^2=b^2+h^2$

substitute

$d^2=(2\sqrt{6})^2+(\sqrt{6})^2$

$d^2=30$

$d=\sqrt{30}\ cm$

3 0

3 years ago

5x +7 y=-17 4x – 3y = -5 Substitute.

Bond [772]

Answer:

(x,y) = (-2, -1)

Step-by-step explanation:

We start off by substituting the value of "x".

5x+7y=-17

x=- $\frac{5}{4} + \frac{3}{4}y$

We then solve 5 $5(-\frac{5}{4}+\frac{3}{4}y ) +7y= -17$

y=-1 *Substitute the value of "y"

x= - $-\frac{5}{4}+\frac{3}{4}x(-1)$

x=-2

$\left \{ {{-17=-17} \atop {-5=-5}} \right.$ This works.

5 0

3 years ago

Ruth borrowed a book from a library. The library charged a fixed rental for the book and a late fee for every day the book was o

DIA [1.3K]

Answer: The second term of the expression which is 0.25x is the variable cost which is the extra amount paid for being late.

The expression 2 + 0.25x represents the amount that Ruth paid for the book.

It should be noted that the fixed cost is represented by 2 while the 0.25 represents the variable cost which is the late fee. Also, the x represented the number of days for being late.

In conclusion, the second term of the expression represents the amount that was charged for being late.

7 0

3 years ago