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Sergio039 [100]
3 years ago
5

What is 2x22x2x2x2x2x2x2x2

Mathematics
2 answers:
Natali [406]3 years ago
4 0
= 2^8 * 22
= 256*22
= 5632
ruslelena [56]3 years ago
4 0
2x22x2x2x2x2x2x2x2 = 5623
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PLEASE I NEED HELP ASAP THANK YOU :) <3
Ainat [17]

Answer: -3

Step-by-step explanation:

The rate of change in a graph is the same as the slope. To find the slope, divide the change in y by the change in x. In this case, it's -9/3, which gets you -3.

7 0
2 years ago
6 2/8 + 4 3/4 whats the answer
gavmur [86]

Answer:

11

Step-by-step explanation:

6 2/8 = 6 1/4

6 1/4 + 4 3/4 = 10 4/4

11

4 0
3 years ago
Read 2 more answers
Can someone help me 10 points
Elanso [62]

The two angles form a right triangle which is 90 degrees.

Add the two to equal 90:

3x-8 + 4x = 90

simplify:

7x-8 = 90

Add 8 to both sides:

7x = 98

Divide both sides by 7:

x = 14

3 0
3 years ago
Find the real or imaginary solutions of each equation by factoring
anyanavicka [17]
Sum of  2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
for x²-4x+16=0
x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}
x=\frac{4+/- \sqrt{16-64} }{2}
x=\frac{4+/- \sqrt{-48} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}
x=\frac{4+/- (i)(4\sqrt{3}) }{2}
x=2+/- 2i\sqrt{3}


the roots are
x=-4 and 2+2i√3 and 2-2i√3
8 0
3 years ago
Find the scale factor of the dilation. Then tell whether it is enlargement or reduction.​
mariarad [96]

Answer:

  a) 1/2; reduction

  b) 5/4; enlargement

Step-by-step explanation:

In each case, the scale factor is CP'/CP. When it is more than 1, the dilation is an enlargement.

Even before you run the numbers, you can tell if it is an enlargement or not. If the dilated figure is larger, P is closer to C than is P'. If P' is closer to C, then it is a reduction.

a) CP'/CP = (4-2)/4 = 2/4 = 1/2 . . . . a reduction

__

b) CP'/CP = 25/20 = 5/4 . . . . an enlargement

4 0
3 years ago
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