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Bogdan [553]
3 years ago
9

Estimate to find the quotient. 342/8=

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

42 3/4 I think

Step-by-step explanation:

because if you simplified 342/8 it will be 171/4. so if you simplified that it'll get you to 42 3/4

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Find the perimeter of a regular nonagon with sides measuring 14.
Andrews [41]

Answer:

126

Step-by-step explanation:

A Nonagon has 9 sides. To answer this, the polygon has to be regular.

The Perimeter is 9*14 = 126

4 0
3 years ago
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Multi step equation 12 threw 14 pls
slega [8]

The computation of the equation shows that the answers will be:

12. 340 units

13. 2(270) + (2 × x) = 690

14. x = 5

<h3>How to compute the equations?</h3>

12. The first equation that's given will be:

(13.50 × x) - (3.65 × x) = 3349

13.50x - 3.65x = 3349

9.85x = 3349

x = 3349/9.85

x = 340

The number to break even is 340 units

13. The equation that can be used to find the perimeter will be:

2(270) + (2 × x) = 690

540 + 2x = 690

2x = 690 - 540

2x = 150

x = 150/2 = 75

14. x + x + 2 + 8 = 20

2x + 10 = 20

2x = 20 - 10

2x = 10

x = 10/2

x = 5

Learn more about equations on:

brainly.com/question/2972832

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4 0
2 years ago
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Find the simple interest on $500 at 6% for one year
Brrunno [24]
600+700 and that’s the answer
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4 years ago
What is the remainder in the division problem
Cerrena [4.2K]
I believe the answer is 2, the 3 large circles are filled with 5 dots each, the total number of dots is 17. 15 is the number closest to 17 that can be divided by 3 therefore there would be 2 left over (the 2 dots on the outside)
6 0
3 years ago
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Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$
KengaRu [80]
\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy
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\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}
=0
4 0
3 years ago
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