All categories

3 years ago

Hi I need help please

Mathematics

2 answers:

xenn [34]3 years ago

5 0

8x-10=62

solve for x

8x=62+10

8x=72

x=72/8

x=9

Sphinxa [80]3 years ago

3 0

Answer:

x = 9

Step-by-step explanation:

8x - 10 = 62

8x = 72

x = 9

You might be interested in

A magazine contains thirteen pages. You

n200080 [17]

Answer:

Step-by-step explanation:

because your more likely to open to a page deeper in the magazine

5 0

3 years ago

Baxter has a sandbox that holds Kinetic sand. The diagram

NARA [144]

It's a cuboid

Length=L=3-3/4=3.75ft
Breadth=11/12ft=0.92ft
Height=H=4ft

Volume:-

LBH
3.75(0.92)(4)
13.8ft²

6 0

2 years ago

Read 2 more answers

Find the HCF of 750,630 and 18900

Sever21 [200]

The answer is:
Hcf=150

3 0

2 years ago

find the volume of the cone. either enter exact answer in terms of pi or use 3.14 for pi and round your final answer to the near

SCORPION-xisa [38]

Answer:

$6\pi u^3 = 18.8u^3$

Step-by-step explanation:

the information we have is:

the radius of the circle in the base: $r=3u$ (u for units)

and the height of the cone: $h=2u$

to find the volume we need the formula for the volume of a cone:

$V=\frac{\pi r^2h}{3}$

where r is the radius and h is the height.

Substituting the known values to find the volume:

$V=\frac{\pi (3u)^2(2u)}{3} \\\\V=\frac{\pi (9u^2)(2u)}{3}\\ \\V=\frac{18\pi u^3}{3}\\ \\V=6\pi u^3$

the volume in terms of $\pi$ is $6\pi u^3$

and if we substitute the value of pi: $\pi=3.14$ we get:

$V=6(3.14)u^3\\V=18.8u^3$

5 0

3 years ago

Read 2 more answers

Find the system of inequalities which represents the shaded region on the coordinate plane.

dybincka [34]

Answer:

given, y≥2x+1 and

x−1

first, draw the graph for equations y=2x+1 and y=

x−1

for y=2x+1

substitute y=0 we get, 2x+1=0⟹x=−0.5

substitute x=0 we get, y=1

therefore, y=2x+1 line passes through (0.5,0) and (0,1) as shown in fig.

Hence, y≥2x+1 includes the region above the line.

for y=

x−1

substitute y=0 we get,

x−1=0⟹x=2

substitute x=0 we get, y=−1

therefore, y=2x+1 line passes through (2,0) and (0,-1) as shown in fig.

Hence, y>

x−1 includes the region above the line.

the intersection region is the shaded region as shown in above figure which includes I, II and III quadrants.

Therefore, quadrant IV has no solution please make as brainlelist

7 0

3 years ago