Answer:
The variable cost per unit is $1.54
Explanation:
Variable costs are those cost which vary with the change in production of units means higher the production higher cost and lower production will result in lower cost e.g Material cost, labor cost etc.
On the other hand fixed cost the cost which does not vary with the production of units. It is fixed no matter what is the level of production.
According to given data:
Total Cost = $500,000
Fixed Cost = $260,000
Variable cost = Total cost - fixed cost
Variable cost = $500,000 $260,000
Variable cost = $240,000
Number of units = 156,000
Variable cost per unit = $240,000 / 156,000 = $1.54 per unit
Commit to buy more in the future
Answer:
Price elasticity of demand Relation
Explanation:
The reason is that the price and demand are inversely proportional to each other. If the price of the product increases the demand of the product will decrease and vice versa. So this means that if the organization wants to generate maximum profit then it will have to set a price that generate maximum demand which means which generates maximum profit. The Bugatti is very expensive and the result is that very fewer people own it in the world but the Mercedes with an above average price has customers in millions, Honda has more than million customers because it is priced average. So the thing is that the pricing matters in deciding how much of the total customers you want.
Answer:
What is the net realizable value of Accounts Receivable after a $ 140$140 account receivable is written off? is $3550
Explanation:
Account receivable 4000
Allowance bad debts 450
Net realizable =(400-140)-(450-140)
=3860-310
=3550
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80