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4 years ago

Evaluate the expression when b=4÷5 and y=-2÷9 3y-b

Mathematics

1 answer:

damaskus [11]4 years ago

8 0

Answer:

-6/45

Step-by-step explanation:

3y-b

=3(2/9) - 4/5

= 6/9 - 4/5

= 30-36/45

=-6/45

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A straight line has gradient -2 and passes through the point (-3 , 10).

Aleksandr-060686 [28]

Answer:

y = 4 - 2x

Step-by-step explanation:

That is the formula, in y = a + mx but it you want it in y = mx+c, it is y = -2x + 4

8 0

2 years ago

A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are

AnnyKZ [126]

Answer:

Step-by-step explanation:

There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

5 0

4 years ago

Fill in the missing value to make the equations true.

Furkat [3]

Answer:

a) 7/4 b) 5 c) 2

Step-by-step explanation:

Logrithmic Rule for a and b

Let a, M, N be positive real numbers.

logaM - logaN = loga(M/N)

log9(7) - log9(4) = log9 (7/4)

logaM + logaN = logaMN

log2 (x) + log2(9) = log2(45)

x9=45

(x9)/9 = 45/9

x = 5

Change of base formula.

logb(x)=logd(b)/logd(x)

x log6(5) = log6(25) divide each term by log6(5)

x log6(5) / log6(5) = log6(25) / log6(5) Cancel common factor log6(5)

x = log6(25) / log6(5)

x = log6(5^2) / log6(5)

Expand log6(5^2) by moving 2 outside the logarithm.

x = 2log6(5) / log6(5) cancel the like term log6(5)

x = 2

7 0

4 years ago

Find a number so that 97.3% of it is 36

tiny-mole [99]

So x is the number
x time 97.3%=36
percent measn parts out of 100 so
97.3%=97.3/100=9.73/10=0.973/1=0.973
x times 0.973=36
divide both sides by 0.973
x=36.9989...
answer is aprox 36.9

7 0

3 years ago

Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN

sashaice [31]

Answer:

The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

and (x2 , y2) are $x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}$

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ $x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}$

∵ $y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}$

∴ The coordinates of the midpoint are $(-2\frac{1}{2},4\frac{1}{2})$

* The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

8 0

3 years ago