Answer:
Mass of Analyte H2C2O4 = 18.18 grams
Explanation:
The balanced equation is:
The Molarity of Oxalic acid needed can be determined using:
Here M1 = Molarity of Oxalic acid
V1 = Volume of oxalic acid
M2 = Molarity of KOH and V2 = Volume of KOH
M1 = ? , V1 = 16.8 mL , M2 = 0.501 M , V2 = 13.54 mL
Put the values and solve for M2,
We are multiplying by 2 because , 1 H2C2O4 needs 2 KOH
Hence Molarity of H2C2O4 =
0.202 M
Molar mass = H2C2O4 = 2x1 +2x12 + 4x16
= 2+24+64 = 90 gram
18.18 gram
Answer:
B
Explanation:
A. Is wrong
This definition in this option does not fully define what an open system entails. It only gave a one sided definition of the phenomenon on ground
B is correct
In an open system, matter and energy should be free to leave
C is incorrect
This is clearly a one sided definition like A and should not be taken serious
D is incorrect
D is talking essentially about what a closed system is
The equation to be used are:
PM = ρRT
PV = nRT
where
P is pressure, M is molar mass, ρ is density, R is universal gas constant (8.314 J/mol·K), T is absolute temperature, V is volume and n is number of moles
The density of air at 23.5°C, from literature, is 1.19035 kg/m³. Its molar mass is 0.029 kg/mol.
PM = ρRT
P(0.029 kg/mol) = (1.19035 kg/m³)(8.314 J/mol·K)(23.5+273 K)
P = 101,183.9 Pa
n = 0.576 g * 1 kg/1000 g * 1 mol/0.029 kg = 0.019862 mol
(101,183.9 Pa)V = (0.019862 mol)(8.314 J/mol·K)(23.5+273 K)
Solving for V,
V = 4.839×10⁻⁴ m³
Since 1 m³ = 1000 L
V = 4.839×10⁻⁴ m³ * 1000
V = 0.484 L
Hello! Those are called the isotopes of those elements!! They have more than just one form and each has it’s own AMU’s so the multiple numbers above different elements, represent the isotopes of those elements. Carbon is a good one just for one example.
Hope this helps you out! Questions please just ask! Thanks!
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