<span>We're diluting the first solution to make the second solution. This means both solutions will contain the same amount of H2SO4 (it's the concentration of it that changes). If you look at it this way, it's easy to find the unknown mass. Call this unknown mass m.
m * 0.875 = 275 g * 0.55 --> m = 173 g
What I'm saying here is 87.5% of the mass of the first solution needs to be the same as 55% of the mass of the second solution, because you're using the same amount of H2SO4 in both.
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</span>
<h3>
Answer:</h3>
16.7 g H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)
[Given] 1.85 mol NaOH
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol NaOH → 1 mol H₂O
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
16.6685 g H₂O ≈ 16.7 g H₂O
This statement lons form because the loss of one or more electrons makes them less stable than their corresponding atoms; this state requires more energy to maintain is FALSE.
- An ion forms when an atom loses or gains one more electrons.
- This loss or gain of electrons causes the ion to gain the stable octet configuration.
- This stable octet configuration requires less energy to maintain than the corresponding atom.
So, since the stable octet configuration of the ion requires less energy than the corresponding atom, the statement is false.
So, the statement lons form because the loss of one or more electrons makes them less stable than their corresponding atoms; this state requires more energy to maintain is FALSE.
Learn more about ions here:
brainly.com/question/3631272
Writing the name for Fe2o3 is a bit more challenging since Fe is a transition metal. this means you need to used parenthesis and Roman Numeral to show the charge on the Fe atoms. in these case each Fe atoms has a charge of +3 so we write Fe2o3 as an iron(III) oxide
