Question

Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . What is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas? Be sure your answer has the correct number of significant digits in it.

Answer 1

Answer:

3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.

Explanation:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Moles of methane gas = $\frac{1.28 g}{16 g/mol}=0.08 mol$

Moles of oxygen gas = $\frac{10.1 g}{32 g/mol}=0.3156 mol$

According to reaction 1 moles of methane gas reacts with 2 mole of oxygen gas.

Then 0.08 moles of methane will recast with:

$\frac{2}{1}\times 0.08 mol=0.16 mol$ oxygen gas

As we can see that moles of methane are in limiting amount , so the amount moles of carbon dioxide will depend upon on moles of methane gas.

Limiting reagent = methane

According to reaction , 1 mole of methane gas gives 1 mol of carbon dioxide gas.

Then 0.08 moles of metahjen gas wuill give :

$\frac{1}{1}\times 0.08 mol=0.08 mol$ of carbon dioxide gas.

Mass of 0.08 mople sof carbon dioxde gas :

$0.08 mol\times 44 g/mol=3.52 g$

3.52 grams is the theoretical yield of carbon dioxide formed from the reaction of of methane and of oxygen gas.