Answer:
Adults $ 17
Students: $8
Step-by-step explanation:
Adults: x
Students: y
a) 25x + 31y = 673
b) 27x +31y = 707
Elimination:
a) -1(25x + 31y = 673) = -25 -31y = -673
a + b
= (-25 -31y = -673) + (27x + 31y = 707)
= 2x = 34
x = 34/2
x = 17
Substitution a or b:
a) 25(17) + 31y = 673
425 + 31y = 673
31y = 673 - 425
31y = 248
y = 248/31
y = 8
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<h3><u>Given</u>:-</h3>
- Volume 6,900 cm^3
- Length = 23 cm
- Width = 10cm
<h3><u>To Find</u>:-</h3>
<h3><u>Solution</u>:-</h3>


Where,
- » l denotes Length
- » w denotes Width
- » h denotes Height







Therefore , the Volume of the Box is 30 cm ³.
Let's start out by setting up three separate equations for each customer.
d = cost of drink, f = cost of fries, h = cost of hamburger
Miller Family: 4h + 3f = 13.27
James: d + h + 2f = 6.33
Steven: 2h + f + d = 7.04
Since the Miller's didn't order any drinks, let's start by using substitution to find the cost of d between James and Steven.
Let's isolate d with James:
d + h + 2f = 6.33
d = 6.33 - h - 2f
Now let's plug that into Steven's equation:
2h + f + d = 7.04
2h + f + (6.33 - h - 2f) = 7.04
h - f + 6.33 = 7.04
h - f = 0.71
h = 0.71 + f
Let's plug that new h into the Miller Family's equation:
4h + 3f = 13.27
4(0.71 + f) + 3f = 13.27
2.84 + 4f + 3f = 13.27
2.84 + 7f = 13.27
7f = 10.43
f = 1.49
So medium fries cost $1.49
Let's plug f back into the Miller Family's equation to get h:
4h + 3f = 13.27
4h + 3(1.49) = 13.27
4h + 4.47 = 13.27
4h = 8.8
h = 2.2
So a hamburger costs $2.20
Let's plug h and f into Steven's equation to calculate d
2h + f + d = 7.04
2(2.2) + (1.49) + d = 7.04
4.4 + 1.49 + d = 7.04
5.89 + d = 7.04
d = 1.15
So a medium drink costs $1.15
The answer is B. Drink = $1.15, Fries = $1.49, Hamburger = $2.20