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puteri [66]
3 years ago
15

Find a single expression that represents the distance from Adam's house to the corner if the distance between Adam's house and J

im's house is represented by the expression "23x − 2."
Mathematics
1 answer:
kvasek [131]3 years ago
7 0
Just subtract the distance between the corner and jims house from 23x - 2 and you'll get your answer. I just got the correct answer.
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1. In the number 7563291 write down the column that the 5 is in
Tasya [4]

Answer:

  1. Hundred Thousands
  2. -4
  3. 90
  4. a-b
  5. 6/14 = 3/7
  6. 1204
  7. 3500 & 3600
  8. I am guessing but I am not sure on how to do this one. x=11
  9. 3/8(6)-1/6(8)=18/48-8/48=10/48=****5/24****
  10. 6.6 repeating
  11. 180-72=108-49=****59****
  12. 5,6,7,8,9
  13. No number 13
  14. 60%
  15. 3.5 or if adding 7% tax then it is 53.50
  16. 8 edges

8 0
3 years ago
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
Kaylis [27]

Answer:

Adults $ 17

Students: $8

Step-by-step explanation:

Adults: x

Students: y

a) 25x + 31y = 673

b) 27x +31y = 707

Elimination:

a) -1(25x + 31y = 673) = -25 -31y = -673

a + b

= (-25 -31y = -673) + (27x + 31y = 707)

= 2x = 34

x = 34/2

x = 17

Substitution a or b:

a) 25(17) + 31y = 673

425 + 31y = 673

31y = 673 - 425

31y = 248

y = 248/31

y = 8

3 0
2 years ago
Can I get an annual subscription
UNO [17]

Hi!to get an annual subscription you need to pay

7 0
2 years ago
Joel wanted his mom to buy a super-sized box of his favorite cereal, but his mom didn't think it would fit in her cupboard. The
Lorico [155]
<h3><u>Given</u>:-</h3>

  • Volume 6,900 cm^3
  • Length = 23 cm
  • Width = 10cm

<h3><u>To Find</u>:-</h3>

  • Height of box ??

<h3><u>Solution</u>:-</h3>

\\\diamond{\underline{\underline{\sf {\;\; Calculating\; Height\;  of  \; box :-}}}}\\

\\ \pink \star \:  \: {\underline{\boxed {\bf{  Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h }}} }\; \red\bigstar  \\

Where,

  • » l denotes Length
  • » w denotes Width
  • » h denotes Height

\\  \sf \implies \: {Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \: 23 \:    \times  \: 10 \:   \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \:  230 \:   \times \:   h} \\

\\  \sf \implies \: {  \: h  \:   = \:   \frac{6900}{230}  \:  } \\

\\  \sf \implies \: {  \: h  \:   = \:   30 \: {cm }^{3}   \:   } \\

\\ \implies{\underline{\boxed{\frak { Height = 30  \: cm^3 }}}} \; \purple\bigstar \:  \\

\\\qquad \rule{120pt}{3pt}\\

Therefore , the Volume of the Box is 30 cm ³.

5 0
2 years ago
The Miller family visited Mama's Kitchen and ordered 4 hamburgers and 3 medium fries and paid $13.27. James ordered a medium dri
ioda
Let's start out by setting up three separate equations for each customer.
d = cost of drink, f = cost of fries, h = cost of hamburger

Miller Family: 4h + 3f = 13.27
James: d + h + 2f = 6.33
Steven: 2h + f + d = 7.04

Since the Miller's didn't order any drinks, let's start by using substitution to find the cost of d between James and Steven.

Let's isolate d with James:
d + h + 2f = 6.33
d = 6.33 - h - 2f

Now let's plug that into Steven's equation:
2h + f + d = 7.04
2h + f + (6.33 - h - 2f) = 7.04
h - f + 6.33 = 7.04
h - f = 0.71
h = 0.71 + f

Let's plug that new h into the Miller Family's equation:
4h + 3f = 13.27
4(0.71 + f) + 3f = 13.27
2.84 + 4f + 3f = 13.27
2.84 + 7f = 13.27
7f = 10.43
f = 1.49

So medium fries cost $1.49

Let's plug f back into the Miller Family's equation to get h:
4h + 3f = 13.27
4h + 3(1.49) = 13.27
4h + 4.47 = 13.27 
4h = 8.8
h = 2.2

So a hamburger costs $2.20

Let's plug h and f into Steven's equation to calculate d

2h + f + d = 7.04
2(2.2) + (1.49) + d = 7.04
4.4 + 1.49 + d = 7.04
5.89 + d = 7.04
d = 1.15

So a medium drink costs $1.15

The answer is B. Drink = $1.15, Fries = $1.49, Hamburger = $2.20
5 0
3 years ago
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