3 years ago

-(10)-^1 a. -1/10 b. -1/-1^10 c. 1/10 d. 10

Mathematics

1 answer:

Zarrin [17]3 years ago

7 0

A would be your answer!

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Step-by-step explanation:

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= [6 - 2.5]

= 3.5

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Step-by-step explanation:

It doesn't really matter but the equation is 2 + 6 not 6 + 2.

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Which of the following is the solution to the differential equation dP/dt+P=10 with the initial condition P(0)=4

Ber [7]

Answer:

Option C. $P=10-6e^{-t}$

Explanation:

1. Separate variables:

$\dfrac{dP}{dt}+P=10\\ \\ \\ \\\dfrac{dP}{dt}=-P+10\\ \\ \\ \dfrac{dP}{-P+10}=dt$

2. Find the indefinite integrals

$-\ln{(10-P)}=t+C$

3. Solve for P

$10-P=e^{-t+C}\\ \\ 10-P=Ke^{-t}\\ \\ P=10-Ke^{-t}$

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4 = 10 - K(e⁰)

4 = 10 - K

K = 10 - 4

K = 6

5. Substitute K = 6 into the integrated equation:

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That is the option C.

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3 years ago

Help me :D i appreciate anyone who can!

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I don’t understand what do we have to do?

Step-by-step explanation:

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