Answer:
see explanation
Step-by-step explanation:
1
2(3x + 1) = 4(x + 2) ← distribute parenthesis on both sides
6x + 2 = 4x + 8 ( subtract 4x from both sides )
2x + 2 = 8 ( subtract 2 from both sides )
2x = 6 ( divide both sides by 2 )
x = 3
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2
6x = 4(x - 3) ← distribute parenthesis
6x = 4x - 12 ( subtract 4x from both sides )
2x = - 12 ( divide both sides by 2 )
x = - 6
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3
2(4x + 7) = 4x + 30 ← distribute parenthesis on left side
8x + 14 = 4x + 30 (subtract 4x from both sides )
4x + 14 = 30 ( subtract 14 from both sides )
4x = 16 ( divide both sides by 4 )
x = 4
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4
50 = - (y + 22) ← distribute parenthesis by - 1
50 = - y - 22 ( add 22 to both sides )
72 = - y ( multiply both sides by - 1 )
- 72 = y , that is
y = - 72
Cosine Law:
c² = a² + b² - 2 a b cos C
Answer:
C ) area of square c² = area of square a² + area of square b²
- area of defect 1 - area of defect 2
Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
675/1000. Simplified it would be 27/40.
