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lyudmila [28]
2 years ago
11

How did American prepare for and fight for the France battle

Chemistry
2 answers:
Anni [7]2 years ago
6 0

Answer:

Explanation:

They first tried to build there army. They did this by passing the Selective Service Act. ... In the next 18 months about 4 million men and women joined the army, but then the army had to be educated.

asambeis [7]2 years ago
5 0

Answer:

their warfare had changed dramatically

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This is an impossible formula. Pretend it is real.
guapka [62]

There are eight moles of oxygen atoms  in 1 mole of Mn_{9}(ClO_{4}) _{2}.

<h3>What is the number of moles of oxygen atoms?</h3>

We know that a compound is composed of atoms. The atoms that make up the molecule are chemically combined. It is usual that the number of atoms in the compound would correspond with the chemical formula.

Now we have the compound  Mn_{9}(ClO_{4}) _{2}. In one mole of the compound we have;

  • 9 Moles of manganese atom
  • 2 moles of chlorine atom
  • 8 moles of oxygen atom

Thus, there are eight moles of oxygen atoms  in 1 mole of Mn_{9}(ClO_{4}) _{2}.

Learn more about atoms;brainly.com/question/1566330

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7 0
1 year ago
Would the glove, the block of wood, and the glass place stay the same temperature?
xxTIMURxx [149]
no. The metal would be the hottest
5 0
2 years ago
What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro
KengaRu [80]

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

3 0
3 years ago
3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

Regards.

6 0
3 years ago
PLEASE HURRY!! WILL GIVE BRAINLIEST!!!!
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Answer:

a

Explanation:

8 0
2 years ago
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